Question

所以我遇到的问题是我从一本书中做的基本数据库应用程序练习。基本上，当您尝试将产品添加到数据库时，如下面的代码所示，它会检查以确保填写所有字段。但是，最后，当它执行查询并且我有 include（'home.php'）时，发生了一些事情，当我返回home.php页面并点击其中一个该页面上的链接，如果其中一个字段留空，我会得到错误。有什么想法吗？

<?php
// Get the product data
$category_id = $_POST['category_id'];
$code = $_POST['code'];
$name = $_POST['name'];
$price = $_POST['price'];

// Validate inputs
if (empty($code) || empty($name) || empty($price) ) {
    $error = "Invalid product data. Check all fields and try again.";
    include('error.php');
} else {
    // If valid, add the product to the database
    require_once('database.php');
    $query = "INSERT INTO products
                 (categoryID, productCode, productName, listPrice)
              VALUES
                 ('$category_id', '$code', '$name', '$price')";
    $db->exec($query);

    // Display the Product List page
   include('home.php') ;
}
?>

home.php没有html / css

<?php
require_once('database.php');

    // Get category ID
    if(!isset($category_id)) {
        $category_id = $_GET['category_id'];
        if (!isset($category_id)) {
            $category_id = 1;
        }
    }

    // Get name for current category
    $query = "SELECT * FROM categories WHERE categoryID = $category_id";
    $category = $db->query($query);
    $category = $category->fetch();
    $category_name = $category['categoryName'];


    // Get all categories
    $query = "SELECT * FROM categories ORDER BY categoryID";
    $categories = $db->query($query);

    // Get products for selected category
    $query = "SELECT * FROM products
              WHERE categoryID = $category_id
              ORDER BY productID";
    $products = $db->query($query);


?>

Answer 1

在home.php文件中，您使用$_GET代替$_POST：

改变这个：

 $category_id = $_GET['category_id'];

要：

$category_id = $_POST['category_id'];

包含函数php从旧代码中给出错误？

1 个答案: