如何使EDT等待后台线程?

时间:2013-11-24 02:06:27

标签: java multithreading backgroundworker swingworker event-dispatch-thread

基于Oracle Concurrency guidelines我正在尝试更新我的GUI。我的问题是,在EDT中的一个新线程中调用了GUI更新,这导致了我很多不同的失败。

以下代码已准备好运行,它是我的GUI更新示例,简单倒计时:

import java.awt.Component;
import java.awt.Container;
import java.awt.GridBagConstraints;
import java.awt.GridBagLayout;
import java.awt.Insets;
import java.awt.Toolkit;
import java.util.Timer;
import java.util.TimerTask;

import javax.swing.JFrame;
import javax.swing.JLabel;
import javax.swing.SwingUtilities;
import javax.swing.SwingWorker;

public class Chronometer2 {

int COUNT = 5000;


CountTask countTask;


    private static final Insets INSETS = new Insets(1, 1, 1, 1);


    public Chronometer2(){

        (countTask= new CountTask()).execute();

    }


    private static void addComponent(Container container, Component component, int gridx, int gridy,
            int gridwidth, int gridheight, int anchor, int fill) {

          GridBagConstraints gbc = new GridBagConstraints(gridx, gridy, gridwidth, gridheight, 1.0, 1.0,
        anchor, fill, INSETS, 0, 0);

          container.add(component, gbc);
          }

    public int returnCount(){

        System.out.println("My count: " + COUNT);
        return COUNT;
    }

       public void decreaseTime() {
            COUNT--;
        }

        public int getTime() {
            return COUNT;
        }


        private class CountTask extends SwingWorker<Void, Chronometer2>{

            @Override
            protected Void doInBackground() throws Exception {
                // TODO Auto-generated method stub



                final JFrame messageFrame = new JFrame();
                final JLabel message = new JLabel("Next query in " + COUNT/1000 + " seconds.");
                messageFrame.setLayout(new GridBagLayout());

                messageFrame.setTitle("Warning");
                messageFrame.setSize(500,100);
                messageFrame.setLocationRelativeTo(null);
                addComponent(messageFrame, message, 0, 0, 1, 1, GridBagConstraints.CENTER, GridBagConstraints.CENTER);
                messageFrame.setVisible(true);

                final Timer timer = new Timer();
                 timer.schedule(new TimerTask() {

                     @Override
                     public void run() {


                             decreaseTime();
                                    message.setText("Preventing connection block. Next query in " + COUNT/1000 + " seconds.");

                                    if(getTime()==0){
                                        messageFrame.dispose();
                                        timer.cancel();
                                    }

                                }
                 }, 1, 1);
                return null;
            }

        }




public static void main(String[] args){
       SwingUtilities.invokeLater(new Runnable() {
           public void run() {
               new Chronometer2();
           }
       });
}

}

由于从主线程调用了样本,因此它正常工作。但是从我的应用程序调用是在EDT中进行的,因为我需要在显示消息之前按下按钮并触发操作。我创建了一个新线程来调用Swing实用程序(不能直接在EDT中调用),即使我遇到问题,因为直到现在我都无法生成EDT等待后台线程完成然后继续下一个查询。这是EDT中的一段代码:

Thread test = new Thread(new Runnable() {

                        @Override
                        public void run() {
                            // TODO Auto-generated method stub
                            try {
                                SwingUtilities.invokeAndWait(new Runnable() {

                                    @Override
                                    public void run() {
                                        // TODO Auto-generated method stub
                                        new CountScreen();
                                    }



                                });
                            } catch (InvocationTargetException e) {
                                // TODO Auto-generated catch block
                                e.printStackTrace();
                            } catch (InterruptedException e) {
                                // TODO Auto-generated catch block
                                e.printStackTrace();
                            }
                        }
                    });
                    test.start();

我还尝试用wait()notifiy()和Timer Task处理这个问题,但问题是一样的;以下是准备运行的其他代码:

import java.awt.Component;
import java.awt.Container;
import java.awt.GridBagConstraints;
import java.awt.GridBagLayout;
import java.awt.Insets;
import java.awt.Toolkit;
import java.util.Timer;
import java.util.TimerTask;

import javax.swing.JFrame;
import javax.swing.JLabel;

public class Chronometer {


    private static final Insets INSETS = new Insets(1, 1, 1, 1);

    private int TIMER = 3000;

public Chronometer(){

    double timeToNext = System.currentTimeMillis() + 30000;
        double timeDifference = 30000;

    final JFrame messageFrame = new JFrame();
    messageFrame.setLayout(new GridBagLayout());

    messageFrame.setTitle("Warning");
    final JLabel message = new JLabel("Next query in " + timeDifference/1000 + " seconds.");
    messageFrame.setSize(500,100);
    messageFrame.setLocationRelativeTo(null);
    addComponent(messageFrame, message, 0, 0, 1, 1, GridBagConstraints.CENTER, GridBagConstraints.CENTER);
    messageFrame.setVisible(true);

    System.out.println(Thread.currentThread().getName());

     final Timer timer = new Timer();
     timer.schedule(new TimerTask() {

         @Override
         public void run() {



                synchronized (timer) {


                     decreaseTime();
                        message.setText("Preventing connection block. Next query in " + TIMER/1000 + " seconds.");

                        if(getTime()==0){

                            System.out.println("Im here");
                            timer.notify();
                            System.out.println("Im here 2");
                            messageFrame.dispose();
                            System.out.println("Im here 3");
                            timer.cancel();
                        }

                    }
             }
     }, 1, 1);

    synchronized (timer) {

       try {

            timer.wait();
        } catch (InterruptedException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }

    }

       System.out.println("Done");

 }



private static void addComponent(Container container, Component component, int gridx, int gridy,
        int gridwidth, int gridheight, int anchor, int fill) {

      GridBagConstraints gbc = new GridBagConstraints(gridx, gridy, gridwidth, gridheight, 1.0, 1.0,
    anchor, fill, INSETS, 0, 0);

      container.add(component, gbc);
      }

public void decreaseTime() {
    TIMER--;
}

public int getTime() {
    return TIMER;
}


public static void main(String[] args){

Chronometer c = new Chronometer();
}

}

所以,我差不多3天想知道,我怎么能解决这个问题呢?任何建议都非常受欢迎;提前谢谢。

1 个答案:

答案 0 :(得分:1)

我找到了自己的答案。停止EDT绝不是一个选择。决不。如果你想像我一样处理一个问题,解决方案比我想象的要简单得多。触发后,侦听器中的操作只是调用另一个线程来处理您想要的任何内容。这可以防止EDT变忙并冻结GUI。这样,您将能够尽可能多地锁定线程,并且我的意思是同步方法,循环或您想要使用的其他内容。我的解决方案我可以考虑阅读这篇文章:main and the GUI Event Dispatch。这真是一篇很棒的文章,让我开始关注摇摆和线程的新内容。希望这对你也有帮助。