Question

SELECT date, id, sum(revenue)
FROM table
WHERE date between '2013-01-01' and '2013-01-08'
GROUP BY date, id
HAVING sum(revenue)>1000

返回收入>＆gt; 1000的行。

SELECT date, id, sum(revenue)
FROM table
WHERE date between '2013-01-01' and '2013-01-08'
AND id IN (SELECT id FROM table where date between '2013-01-01' and '2013-01-08' GROUP BY id HAVING sum(revenue)>1000)
GROUP BY date, id

返回id的行，其日期间的总收入根据需要为> 1000。但是这个查询要慢得多。有没有更快的方法呢？

Answer 1

确保您在date和id列上有索引，并尝试以下变体：

select t.date, t.id, sum(t.revenue)
from table t
inner join (
    select id
    from table
    where date between '2013-01-01' and '2013-01-08'
    group by id
    having sum(revenue) > 1000
) ts on t.id = ts.id
where t.date between '2013-01-01' and '2013-01-08'
group by t.date, t.id

Answer 2

它不是MySQL，它是Vertica;）

Cris，您在order by ???

中使用的投影和CREATE TABLE

您尝试使用database designer吗？见http://my.vertica.com/docs/6.1.x/HTML/index.htm#14415.htm

有效地按列聚合分组

2 个答案: