Question

我正在尝试从文本文件中读取并且对于非打印ascii字符，我想打印出“^”+“G”作为BELL字符的示例。很像unix的cat -v命令。问题发生在for循环中，我应该存储字符，直到我按下换行符然后打印出来。 for循环为ctrl + G打印“G”，为测试打印“t”“e”“s”“t”。

int readFile(FILE* inputFile) {

char input[5];
char *arrayEnd = &input[5]+1;

int anyChanges = 1;
int iochar = 0;
int i = 0;
//get index of new line
//substring of position until new line
//print substring position to end.
int printedColumns = 0;
//credit Foster Chapter 2
while (( iochar = getc(inputFile) ) != EOF )
{   //Returns 1 if no changes made, return 0 if any changes have been made.
    //printf("character --> %c\n",iochar);
    if(iochar != '\n') {
        //This if statement checks for normal ascii characters.
        //If the output is less than 72 it prints it and increments printedColumns.
        if (( ' ' <= iochar ) && ( iochar <= 126 ) ) {
            if(*(input + i) == *arrayEnd)
            {
                i = 0;
            }
            *(input +i) = iochar;
            //printf("input array ---> %c\n",input[i]);
            //printf("i:%d\n",i);
            //printf("iochar:%d\n",iochar);
            //putc(*(input+i), stdout);
            i++;
            }
        //This if statement checks for the non-printing characters.
        //New line is not included because it is a special case that is accounted for below
        if (iochar <= 31)  {

            if (*(input + i) == *arrayEnd)
            {
                i = 0;
            }
                *(input + i) =94;
                  putc(*(input+i), stdout);
                i++;

            if(*(input+i)== *arrayEnd)
            {
               i = 0;
            }
                *(input + i) = iochar + 64;
                putc(*(input+i), stdout);
                printf("\n");
                i++;

        }
        int b = 0;
        for (b = 0;b<6;b++){
            putc(*(input+b),stdout);
        }
}//end if != '\n'
}//end while
return anyChanges;
}//end function

Answer 1

这似乎做了很多你正在寻找的东西：

#include <stdio.h>

static
int readFile(FILE *inputFile)
{
    int numChanged = 0;
    int iochar = 0;

    while ((iochar = getc(inputFile) ) != EOF)
    {
        if ((' ' <= iochar && iochar <= 126) || iochar == '\n')
            putc(iochar, stdout);
        else if (iochar < ' ')
        {
            putc('^', stdout);
            putc(iochar + 'A' - 1, stdout);
            numChanged++;
        }
        else
            numChanged++;
    }
    return numChanged;
}

int main(void)
{
    printf("Number of changed characters: %d\n", readFile(stdin));
    return 0;
}

它在自己的源代码上正常工作（没有要更改的字符 - 源代码中没有选项卡），它似乎也可以在自己的二进制文件上正常工作。这两种输出都不足以引用。请注意，它会删除代码0x7F到0xFF中的字符。您可以通过适当调整else子句来修改它，以适用于您指定的任何规则。对于这些角色的处理问题没有提及。

如果你需要一行的最后72个字符，那么你需要阅读整行;滚动fgets()：

#include <stdio.h>
#include <string.h>

static
int readFile(FILE *fp)
{
    int numChanged = 0;
    char line[4096];

    while (fgets(line, sizeof(line), fp) != 0)
    {
        size_t len = strlen(line);
        if (line[len-1] != '\n')
            break;  // Damn! Line to long
        size_t start = 0;
        if (len > 72)
            start = len - 72;
        for (size_t i = start; i < len; i++)
        {
            /* The next line is only 70 characters long, but this comment should be truncated */
            if ((' ' <= line[i] && line[i] <= 126) || line[i] == '\n')
                putc(line[i], stdout);
            else if (line[i] < ' ')
            {
                putc('^', stdout);
                putc(line[i] + 'A' - 1, stdout);
                numChanged++;
            }
            else
                numChanged++;
        }
    }
    return numChanged;
}

int main(void)
{
    printf("Number of changed characters: %d\n", readFile(stdin));
    return 0;
}

这段代码独立运行，经过精心设计的源代码，产生了有趣的部分：

            start = len - 72;
        for (size_t i = start; i < len; i++)
        {
ine is only 70 characters long, but this comment should be truncated */
            if ((' ' <= line[i] && line[i] <= 126) || line[i] == '\n')
                putc(line[i], stdout);
            else if (line[i] < ' ')
            {

您可以决定在计算长度时是否有一个错误。

C for循环迭代不同于putc的数组

1 个答案: