我遇到以下示例代码的问题:
from multiprocessing import Lock, Process, Queue, current_process
def worker(work_queue, done_queue):
for item in iter(work_queue.get, 'STOP'):
print("adding ", item, "to done queue")
#this works: done_queue.put(item*10)
done_queue.put(item*1000) #this doesnt!
return True
def main():
workers = 4
work_queue = Queue()
done_queue = Queue()
processes = []
for x in range(10):
work_queue.put("hi"+str(x))
for w in range(workers):
p = Process(target=worker, args=(work_queue, done_queue))
p.start()
processes.append(p)
work_queue.put('STOP')
for p in processes:
p.join()
done_queue.put('STOP')
for item in iter(done_queue.get, 'STOP'):
print(item)
if __name__ == '__main__':
main()
当完成队列变得足够大(我认为限制大约64k)时,整个事情会冻结而不再进一步通知。
当队列变得太大时,这种情况的一般方法是什么?有没有办法在处理后动态删除元素? The Python docs recommend removing the p.join(),在实际应用中,我无法估计进程何时完成。除了无限循环和使用.get_nowait()之外,还有一个简单的解决方案吗?
答案 0 :(得分:1)
这适用于3.4.0alpha4,3.3,3.2,3.1和2.6。它追溯2.7和3.0。我想它,顺便说一句。
#!/usr/local/cpython-3.3/bin/python
'''SSCCE for a queue deadlock'''
import sys
import multiprocessing
def worker(workerno, work_queue, done_queue):
'''Worker function'''
#reps = 10 # this worked for the OP
#reps = 1000 # this worked for me
reps = 10000 # this didn't
for item in iter(work_queue.get, 'STOP'):
print("adding", item, "to done queue")
#this works: done_queue.put(item*10)
for thing in item * reps:
#print('workerno: {}, adding thing {}'.format(workerno, thing))
done_queue.put(thing)
done_queue.put('STOP')
print('workerno: {0}, exited loop'.format(workerno))
return True
def main():
'''main function'''
workers = 4
work_queue = multiprocessing.Queue(maxsize=0)
done_queue = multiprocessing.Queue(maxsize=0)
processes = []
for integer in range(10):
work_queue.put("hi"+str(integer))
for workerno in range(workers):
dummy = workerno
process = multiprocessing.Process(target=worker, args=(workerno, work_queue, done_queue))
process.start()
processes.append(process)
work_queue.put('STOP')
itemno = 0
stops = 0
while True:
item = done_queue.get()
itemno += 1
sys.stdout.write('itemno {0}\r'.format(itemno))
if item == 'STOP':
stops += 1
if stops == workers:
break
print('exited done_queue empty loop')
for workerno, process in enumerate(processes):
print('attempting process.join() of workerno {0}'.format(workerno))
process.join()
done_queue.put('STOP')
if __name__ == '__main__':
main()
HTH