Question

我编写了以下bash代码来检测SSL证书是否存在，如果存在，则跳过创建一个。

我需要扩展检测到的文件列表，这样任何文件都会跳过SSL证书的创建。

完整的文件列表是“trailers.cer”或“trailers.key”或“trailers.pem”

检测后的方法是提示用户询问是否要创建SSL证书

file="assets/certificates/trailers.cer"
if [ -f "$file" ]; then
echo 'SSL Certificates already created' 
else
openssl req -new -nodes -newkey rsa:2048 -out ./assets/certificates/trailers.pem -keyout ./assets/certificates/trailers.key -x509 -days 7300 -subj "/C=US/CN=trailers.apple.com"
openssl x509 -in ./assets/certificates/trailers.pem -outform der -out ./assets/certificates/trailers.cer && cat ./assets/certificates/trailers.key >> ./assets/certificates/trailers.pem
fi

Answer 1

假设退出整个脚本就足够了，

for file in trailers.cer trailers.key /assets/certificates/trailers.pem; do
    test -f "$file" && exit 1 # or even 0?
done
# If you reach through here, none existed

我将其中一个项目更改为绝对路径，以显示它是如何完成的。如果所有文件的路径相同，则可以重构以后提供路径; test -f "/assets/certificates/$file"

Answer 2

您可以在if中使用多个test和||添加多个条件，如下所示：

if test -f "$path1" || test -f "$path2" || test -f "$path3"; then
    ...
fi

当文件很多时，使用数组可以更容易和更易读，如下所示：

#!/bin/bash

basedir=assets/certificates
files=(trailers.cer trailers.key trailers.pem)

found=
for file in ${files[@]}; do
    path="$basedir/$file"
    if [ -f "$path" ]; then
        echo SSL Certificates already created
        found=1
        break
    fi
done

if test ! "$found"; then
    openssl req -new -nodes -newkey rsa:2048 -out ./assets/certificates/trailers.pem -keyout ./assets/certificates/trailers.key -x509 -days 7300 -subj "/C=US/CN=trailers.apple.com"
    openssl x509 -in ./assets/certificates/trailers.pem -outform der -out ./assets/certificates/trailers.cer && cat ./assets/certificates/trailers.key >> ./assets/certificates/trailers.pem
fi

检测if语句中的多个文件

2 个答案: