我正在使用的IDE(visual studio 2012)没有显示任何错误或警告,但我基本上试图将二进制数据写入名为wizdata.bin的文件中,并且我已经声明了我的向导的一些对象类。 Wizard类具有很少的函数,包含4个成员变量(1个字符串和3个int)。当我在Wizard类中调用名为“save”的函数时,控制台程序停止工作,但它确实设法编写了一个String类成员变量名称。之后它无法在类中编写任何一个int。所以问题是我在尝试将int写入二进制文件时遇到了什么问题?在Wizard.cpp中受到赞扬的部分导致了崩溃。
继承我的代码文件:
Wizard.h:
#ifndef WIZARD_H
#define WIZARD_H
#include <string>
#include <fstream>
class Wizard
{
public:
Wizard();
Wizard( std::string name, int hp, int mp, int armor );
void print();
void save( std::ofstream& outFile );
void load( std::ifstream& inFile );
private:
std::string name;
int hitPoints;
int magicPoints;
int armor;
};
#endif
Wizard.cpp:
#include "Wizard.h"
#include <iostream>
using namespace std;
Wizard::Wizard()
{
name = "Default";
hitPoints = 0;
magicPoints = 0;
armor = 0;
}
Wizard::Wizard( string name, int hp, int mp, int armor )
{
this->name = name;
hitPoints = hp;
magicPoints = mp;
this->armor = armor;
}
void Wizard::print()
{
cout << "Name= " << name << endl;
cout << "HP= " << hitPoints << endl;
cout << "MP= " << magicPoints << endl;
cout << "Armor= " << armor << endl;
cout << endl;
}
void Wizard::save( ofstream& outFile )
{
outFile.write( name.c_str(), name.size() );
//outFile.write( (char*)hitPoints, sizeof(hitPoints) );
//outFile.write( (char*)magicPoints, sizeof(magicPoints) );
//outFile.write( (char*)armor, sizeof(armor) );
}
void Wizard::load( ifstream& inFile )
{
inFile.read( (char*)name.c_str(), name.size() );
inFile.read( (char*)&hitPoints, sizeof(hitPoints) );
inFile.read( (char*)&magicPoints, sizeof(magicPoints) );
inFile.read( (char*)&armor, sizeof(armor) );
}
和Main.cpp:
#include "Wizard.h"
using namespace std;
int main()
{
Wizard wiz0( "Gandalf", 25, 100, 10 );
Wizard wiz1( "Loki", 50, 150, 12 );
Wizard wiz2( "Magius", 10, 75, 6 );
ofstream outFile;
outFile.open( "wizdata.bin", ios_base::binary );
if( outFile )
{
wiz0.save( outFile );
wiz1.save( outFile );
wiz2.save( outFile );
outFile.close();
}
return 0;
}
这是我加载数据的第二个控制台应用程序的“Main.cpp”:
#include "Wizard.h"
#include <iostream>
using namespace std;
int main()
{
Wizard wiz0;
Wizard wiz1;
Wizard wiz2;
cout << "BEFORE LOADING..." << endl;
wiz0.print();
wiz1.print();
wiz2.print();
ifstream inFile;
inFile.open( "wizdata.bin", ios_base::binary );
if( inFile )
{
wiz0.load( inFile );
wiz1.load( inFile );
wiz2.load( inFile );
inFile.close();
}
cout << "AFTER LOADING..." << endl;
wiz0.print();
wiz1.print();
wiz2.print();
return 0;
}
加载数据后,这些是值: 姓名:甘道夫 惠普:25 MP:100 护甲:10
姓名:Loki2 惠普:38400 议员:3072 护甲:1734429952
姓名:ius 惠普:75 议员:6 护甲:0
答案 0 :(得分:1)
简短回答:
使用移位运算符'&lt;&lt;'而不是写()。
稍微长一点回答:
问题在于演员。 (char *)数字将数字解释为指针,当然不能指向任何有意义的数字。
答案 1 :(得分:0)
write的第一个参数应该是指向要写入的数据的指针。所以试试这个:
outFile.write( (char*)&hitPoints, sizeof(hitPoints) );