使用Java计算两个日期之间的天数

时间：2013-11-23 17:31:23

标签： java date-arithmetic

我想要一个Java程序来计算两个日期之间的天数。

  1. 输入第一个日期（德语表示法;带空格：“dd mm yyyy”）
  2. 输入第二个日期。
  3. 程序应计算两个日期之间的天数。

    4. 我如何包括闰年和夏季？

    我的代码：

    import java.util.Calendar;
import java.util.Date;
import java.util.Scanner;

public class NewDateDifference {

    public static void main(String[] args) {

        System.out.print("Insert first date: ");
        Scanner s = new Scanner(System.in);
        String[] eingabe1 = new String[3];

        while (s.hasNext()) {
            int i = 0;
            insert1[i] = s.next();
            if (!s.hasNext()) {
                s.close();
                break;
            }
            i++;
        }

        System.out.print("Insert second date: ");
        Scanner t = new Scanner(System.in);
        String[] insert2 = new String[3];

        while (t.hasNext()) {
            int i = 0;
            insert2[i] = t.next();
            if (!t.hasNext()) {
                t.close();
                break;
            }
            i++;
        }

        Calendar cal = Calendar.getInstance();

        cal.set(Calendar.DAY_OF_MONTH, Integer.parseInt(insert1[0]));
        cal.set(Calendar.MONTH, Integer.parseInt(insert1[1]));
        cal.set(Calendar.YEAR, Integer.parseInt(insert1[2]));
        Date firstDate = cal.getTime();

        cal.set(Calendar.DAY_OF_MONTH, Integer.parseInt(insert2[0]));
        cal.set(Calendar.MONTH, Integer.parseInt(insert2[1]));
        cal.set(Calendar.YEAR, Integer.parseInt(insert2[2]));
        Date secondDate = cal.getTime();


        long diff = secondDate.getTime() - firstDate.getTime();

        System.out.println ("Days: " + diff / 1000 / 60 / 60 / 24);
    }
}

14 个答案:

答案 0 :(得分：197)

您正在使用不必要的字符串进行一些转换。它有一个SimpleDateFormat类 - 试试这个：

SimpleDateFormat myFormat = new SimpleDateFormat("dd MM yyyy");
String inputString1 = "23 01 1997";
String inputString2 = "27 04 1997";

try {
    Date date1 = myFormat.parse(inputString1);
    Date date2 = myFormat.parse(inputString2);
    long diff = date2.getTime() - date1.getTime();
    System.out.println ("Days: " + TimeUnit.DAYS.convert(diff, TimeUnit.MILLISECONDS));
} catch (ParseException e) {
    e.printStackTrace();
}

编辑：由于对此代码的正确性进行了一些讨论：它确实照顾了闰年。但是，TimeUnit.DAYS.convert函数会丢失精度，因为毫秒将转换为天数（有关详细信息，请参阅链接的文档）。如果这是一个问题，diff也可以手动转换：

float days = (diff / (1000*60*60*24));

请注意，这是float值，不一定是int。

答案 1 :(得分：86)

最简单的方法：

public static long getDifferenceDays(Date d1, Date d2) {
    long diff = d2.getTime() - d1.getTime();
    return TimeUnit.DAYS.convert(diff, TimeUnit.MILLISECONDS);
}

答案 2 :(得分：64)

在Java 8中，您可以使用public void login(final LoginCallback loginCallback) { mApiService.login( developerKey, applicationKey, new Callback<User>() { @Override public void success ( User user, Response response ) { //code which should update user field loginCallback.ready(); } @Override public void failure ( RetrofitError error ) { } } ); 和LocalDate来完成此操作。来自DateTimeFormatter的{​​{3}}：

  

LocalDate是一个表示日期的不可变日期时间对象，   通常被视为年月日。

可以使用LocalDate构建模式。这是Javadoc，以及我使用的相关模式字符：

  

符号 - 含义 - 演示文稿 - 示例

     

y - 年代 - 年 - 2004年; 04

     

M / L - 一年中的月份 - 数字/文字 - 7; 07; 7月;   七月; Ĵ

     

d - 每月 - 数字 - 10

以下是示例：

DateTimeFormatter

最近的最后一个输入/输出示例：

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.time.LocalDate;
import java.time.format.DateTimeFormatter;
import java.time.temporal.ChronoUnit;

public class Java8DateExample {
    public static void main(String[] args) throws IOException {
        final DateTimeFormatter formatter = DateTimeFormatter.ofPattern("dd MM yyyy");
        final BufferedReader reader = new BufferedReader(new InputStreamReader(System.in));
        final String firstInput = reader.readLine();
        final String secondInput = reader.readLine();
        final LocalDate firstDate = LocalDate.parse(firstInput, formatter);
        final LocalDate secondDate = LocalDate.parse(secondInput, formatter);
        final long days = ChronoUnit.DAYS.between(firstDate, secondDate);
        System.out.println("Days between: " + days);
    }
}

最近的第一次：

23 01 1997
27 04 1997
Days between: 94

嗯，你可以用更简单的方式做一个方法：

27 04 1997
23 01 1997
Days between: -94

答案 3 :(得分：56)

当夏令时出现时，大多数/所有答案都会给我们带来问题。这是我们针对所有日期的工作解决方案，而不使用JodaTime。它使用日历对象：

public static int daysBetween(Calendar day1, Calendar day2){
    Calendar dayOne = (Calendar) day1.clone(),
            dayTwo = (Calendar) day2.clone();

    if (dayOne.get(Calendar.YEAR) == dayTwo.get(Calendar.YEAR)) {
        return Math.abs(dayOne.get(Calendar.DAY_OF_YEAR) - dayTwo.get(Calendar.DAY_OF_YEAR));
    } else {
        if (dayTwo.get(Calendar.YEAR) > dayOne.get(Calendar.YEAR)) {
            //swap them
            Calendar temp = dayOne;
            dayOne = dayTwo;
            dayTwo = temp;
        }
        int extraDays = 0;

        int dayOneOriginalYearDays = dayOne.get(Calendar.DAY_OF_YEAR);

        while (dayOne.get(Calendar.YEAR) > dayTwo.get(Calendar.YEAR)) {
            dayOne.add(Calendar.YEAR, -1);
            // getActualMaximum() important for leap years
            extraDays += dayOne.getActualMaximum(Calendar.DAY_OF_YEAR);
        }

        return extraDays - dayTwo.get(Calendar.DAY_OF_YEAR) + dayOneOriginalYearDays ;
    }
}

答案 4 :(得分：13)

最好的方法，它转换为String作为奖励;）

protected void onCreate(Bundle savedInstanceState) {

    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);
    try {
        //Dates to compare
        String CurrentDate=  "09/24/2015";
        String FinalDate=  "09/26/2015";

        Date date1;
        Date date2;

        SimpleDateFormat dates = new SimpleDateFormat("MM/dd/yyyy");

        //Setting dates
        date1 = dates.parse(CurrentDate);
        date2 = dates.parse(FinalDate);

        //Comparing dates
        long difference = Math.abs(date1.getTime() - date2.getTime());
        long differenceDates = difference / (24 * 60 * 60 * 1000);

        //Convert long to String
        String dayDifference = Long.toString(differenceDates);

        Log.e("HERE","HERE: " + dayDifference);
    }
    catch (Exception exception) {
        Log.e("DIDN'T WORK", "exception " + exception);
    }
}

答案 5 :(得分：9)

众所周知，Java日期库已被破坏。我建议使用Joda Time。它会照顾闰年，时区等等。

最小的工作示例：

import java.util.Scanner;
import org.joda.time.DateTime;
import org.joda.time.Days;
import org.joda.time.LocalDate;
import org.joda.time.format.DateTimeFormat;
import org.joda.time.format.DateTimeFormatter;

public class DateTestCase {

    public static void main(String[] args) {

        System.out.print("Insert first date: ");
        Scanner s = new Scanner(System.in);
        String firstdate = s.nextLine();
        System.out.print("Insert second date: ");
        String seconddate = s.nextLine();

        // Formatter
        DateTimeFormatter dateStringFormat = DateTimeFormat
                .forPattern("dd MM yyyy");
        DateTime firstTime = dateStringFormat.parseDateTime(firstdate);
        DateTime secondTime = dateStringFormat.parseDateTime(seconddate);
        int days = Days.daysBetween(new LocalDate(firstTime),
                                    new LocalDate(secondTime)).getDays();
        System.out.println("Days between the two dates " + days);
    }
}

答案 6 :(得分：8)

使用：

public int getDifferenceDays(Date d1, Date d2) {
    int daysdiff = 0;
    long diff = d2.getTime() - d1.getTime();
    long diffDays = diff / (24 * 60 * 60 * 1000) + 1;
    daysdiff = (int) diffDays;
    return daysdiff;
}

答案 7 :(得分：5)

String dateStart = "01/14/2015 08:29:58";
String dateStop = "01/15/2015 11:31:48";

//HH converts hour in 24 hours format (0-23), day calculation
SimpleDateFormat format = new SimpleDateFormat("MM/dd/yyyy HH:mm:ss");

Date d1 = null;
Date d2 = null;

d1 = format.parse(dateStart);
d2 = format.parse(dateStop);

//in milliseconds
long diff = d2.getTime() - d1.getTime();

long diffSeconds = diff / 1000 % 60;
long diffMinutes = diff / (60 * 1000) % 60;
long diffHours = diff / (60 * 60 * 1000) % 24;
long diffDays = diff / (24 * 60 * 60 * 1000);

System.out.print(diffDays + " days, ");
System.out.print(diffHours + " hours, ");
System.out.print(diffMinutes + " minutes, ");
System.out.print(diffSeconds + " seconds.");

答案 8 :(得分：1)

当我运行你的程序时，它甚至没有得到我 到了我可以进入第二个约会的地步。

这更简单，更不容易出错。

import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.text.SimpleDateFormat;
import java.util.Date;

public class Test001 {

    public static void main(String[] args) throws Exception {

        BufferedReader br = null;

        br = new BufferedReader(new InputStreamReader(System.in));
        SimpleDateFormat sdf = new SimpleDateFormat("dd MM yyyy");

        System.out.println("Insert first date : ");
        Date dt1 = sdf.parse(br.readLine().trim());

        System.out.println("Insert second date : ");
        Date dt2 = sdf.parse(br.readLine().trim());

        long diff = dt2.getTime() - dt1.getTime();

        System.out.println("Days: " + diff / 1000L / 60L / 60L / 24L);

        if (br != null) {
            br.close();
        }
    }
}

答案 9 :(得分：1)

// date format, it will be like "2015-01-01"
private static final String DATE_FORMAT = "yyyy-MM-dd";

// convert a string to java.util.Date
public static Date convertStringToJavaDate(String date)
        throws ParseException {
    DateFormat dataFormat = new SimpleDateFormat(DATE_FORMAT);
    return dataFormat.parse(date);
}

// plus days to a date
public static Date plusJavaDays(Date date, int days) {
    // convert to jata-time
    DateTime fromDate = new DateTime(date);
    DateTime toDate = fromDate.plusDays(days);
    // convert back to java.util.Date
    return toDate.toDate();
}

// return a list of dates between the fromDate and toDate
public static List<Date> getDatesBetween(Date fromDate, Date toDate) {
    List<Date> dates = new ArrayList<Date>(0);
    Date date = fromDate;
    while (date.before(toDate) || date.equals(toDate)) {
        dates.add(date);
        date = plusJavaDays(date, 1);
    }
    return dates;
}

答案 10 :(得分：1)

我们可以使用LocalDate和ChronoUnit Java库，下面的代码可以正常工作。 日期应采用yyyy-MM-dd格式。

import java.time.LocalDate;
import java.time.temporal.ChronoUnit;
import java.util.*;
class Solution {
    public int daysBetweenDates(String date1, String date2) {
        LocalDate dt1 = LocalDate.parse(date1);
        LocalDate dt2= LocalDate.parse(date2);

        long diffDays = ChronoUnit.DAYS.between(dt1, dt2);

        return Math.abs((int)diffDays);
    }
}

答案 11 :(得分：1)

以下对我来说效果很好：

public int daysBetween(LocalDate later, LocalDate before) {
        SimpleDateFormat myFormat = new SimpleDateFormat("dd MM yyyy");
        int daysBetween = 0;
        try {
            Date dateBefore = myFormat.parse(localDateToString(before));
            Date dateAfter = myFormat.parse(localDateToString(later));
            long difference = dateAfter.getTime() - dateBefore.getTime();
            daysBetween = (int) (difference / (1000 * 60 * 60 * 24));
        } catch (Exception e) {
            e.printStackTrace();
        }
        return daysBetween;
    }

    public String localDateToString(LocalDate date) {
        DateTimeFormatter myFormat = DateTimeFormatter.ofPattern("dd MM yyyy");
        return date.format(myFormat).toString();
    }

答案 12 :(得分：0)

public class TestCode {

    public static void main(String[] args) {        
        String date1 = "23-04-2021";
        String date2 = "24-05-2021";
        System.out.println("NDays: " + nDays_Between_Dates(date1, date2));      
    }
    
    public static int nDays_Between_Dates(String date1, String date2) {
        int diffDays = 0;
        try {
            SimpleDateFormat dates = new SimpleDateFormat("dd-MM-yyyy");
            Date startDate = dates.parse(date1);
            Date endDate = dates.parse(date2);
            long diff = endDate.getTime() - startDate.getTime();
            diffDays = (int) (diff / (24 * 60 * 60 * 1000));            
        } catch (ParseException e) {
            e.printStackTrace();
        }
        return Math.abs(diffDays);
    }
}

输出：NDays：31

答案 13 :(得分：0)

想要几天（没有时间）你可以使用 ChronoUnit

ChronoUnit.DAYS.between(date1.toLocalDate(), date2.toLocalDate());
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