Question

我目前正在使用php进行项目。在这里，我想使用move_uploaded_file将图像存储到文件夹中，但是当我使用以下代码时：

if (move_uploaded_file($_FILES['file_promo_image']['tmp_name'], $uploadfile))
    {
        echo "Le fichier est valide, et a été téléchargé avec succès.\n";

    }

我收到以下错误：

Warning:  move_uploaded_file(http://www.desgensbien.com/sites/bestinfo/images/news/CodeCogsEqn.gif) [function.move-uploaded-file]: failed to open stream: HTTP wrapper does not support writeable connections. in /homez.534/desgensb/www/sites/bestinfo/admin/record-news.php on line 73



Warning:  move_uploaded_file() [function.move-uploaded-file]: Unable to move '/tmp/phpfCHv2s' to 'http://www.desgensbien.com/sites/bestinfo/images/news/CodeCogsEqn.gif' in /homez.534/desgensb/www/sites/bestinfo/admin/record-news.php on line 73

如何解决此问题

Answer 1

使用此：

$uploadfile = $_SERVER['DOCUMENT_ROOT'] . '/sites/bestinfo/images/news/CodeCogsEqn.gif';

Answer 2

你好

我知道这张票已经开了一段时间但是我一直在寻找这个完整的代码一段时间我只在网上找到它的一部分但没有完全有效，所以这里是。 我希望它可以帮助一些人。

我看到了你的帖子，我使用了here发现的大部分信息都是完全相同的问题 - 下面代码的主要作者是w3schools。

以下是两种方式：

1-您的上传表单或功能位于接收文件

的服务器上

// the index.php file on the server
<br><br>
<?php /* includes */ require_once 'upload.php'; ?>

<!DOCTYPE html>
<html><body> Formulaire de téléchargement d'une image <br><br>

<form action="upload.php" method="POST" enctype="multipart/form-data">
    Select image to upload:
    <input type="file" name="fileToUpload" id="fileToUpload">
    <input type="submit" value="Upload Image" name="submit">
</form>
</body> </html>

upload.php文件，在本例中为同一个目录

<?php
// writing in a sublfolder called image 
$target_dir = "image/";
$target_file = $target_dir . basename($_FILES["fileToUpload"]["name"]);
$uploadOk = 1;
$imageFileType = pathinfo($target_file,PATHINFO_EXTENSION);

// Check if image file is a actual image or fake image
if(isset($_POST["submit"])) {
    $check = getimagesize($_FILES["fileToUpload"]["tmp_name"]);
    if($check !== false) {
        echo "File is an image - " . $check["mime"] . ".";
        $uploadOk = 1;
    } else {
        echo "File is not an image.";
        $uploadOk = 0;
    }
}
if ($uploadOk == 0) {
    echo "Sorry, your file was not uploaded.";
// if everything is ok, try to upload file
} else {

    // give a name and direction to the image - i changed the name to test.jpg...
    $uploadfile = $_SERVER['DOCUMENT_ROOT'].$target_dir.'test.jpg';
    echo "<br><br>";
    echo $uploadfile;
         echo "<br><br>";

    if (move_uploaded_file($_FILES["fileToUpload"]["tmp_name"], $uploadfile)) {
        echo "The file ". basename( $_FILES["fileToUpload"]["name"]). " has been uploaded.";
    } else {
        echo "Sorry, there was an error uploading your file.";
    }
}

?>

2-秒选项，如果您的网络服务器与接收文件的服务器不同，则每个服务器上需要有两个文件：

发送文件的服务器（您的网络服务器）：send.php

<?php
    // I uploaded a file called sample2.jpeg from on server to another
    // again you can make functions out of this
    $target_url = 'http://192.168.56.103/receive.php';
        //This needs to be the full path to the file you want to send.


$file_name_with_full_path = realpath('./sample2.jpeg');
            /* curl will accept an array here too.
             * Many examples I found showed a url-encoded string instead.
             * Take note that the 'key' in the array will be the key that shows up in the
             * $_FILES array of the accept script
             */
        //$post = array('extra_info' => '123456','file_contents'=>'@'.$file_name_with_full_path);
        $post = array('file_contents' => new CurlFile($file_name_with_full_path, 'text/plain' /* MIME-Type */,'' /*directory*/));

            $ch = curl_init();
        curl_setopt($ch, CURLOPT_URL,$target_url);
        curl_setopt($ch, CURLOPT_POST,1);
        curl_setopt($ch, CURLOPT_POSTFIELDS, $post);
            curl_setopt($ch, CURLOPT_RETURNTRANSFER,1);
        $result=curl_exec ($ch);
        curl_close ($ch);
        echo $result;
    ?>

接收服务器上的文件结束：receive.php

<?php
// you can chage the destination path
$uploaddir = realpath('./') . '/';
$uploadfile = $uploaddir . basename($_FILES['file_contents']['name']);

echo "<br><br>";
print_r ($uploadfile);
echo "<br><br>";

echo '<pre>';
        if (move_uploaded_file($_FILES['file_contents']['tmp_name'], $uploadfile)) {
            echo "File is valid, and was successfully uploaded.\n";
        } else {
            echo "Possible file upload attack!\n";
        }
        echo 'Here is some more debugging info:';
        print_r($_FILES);
        echo "\n<hr />\n";
        print_r($_POST);
print "</pr" . "e>\n";
?>



<br><br>Sources and references to other codes : 
<br>http://stackoverflow.com/questions/12667797/using-curl-to-upload-post-data-with-files
<br>http://stackoverflow.com/questions/15200632/how-to-upload-file-using-curl-with-php
<br>http://code.stephenmorley.org/php/sending-files-using-curl/
<br>http://www.w3schools.com/php/php_file_upload.asp

再次感谢99％代码的真实作者，并在stackoverflow论坛上发表了人们评论：derakkilgo和W3SCHOOLS。

Answer 3

很简单……这是FTP的主要精髓；跨域写入数据。使用PHP FTP 功能上传文件。您可以在此处查看参考库 >> FTP_FPUT()

使用move_uploaded_file获取错误HTTP包装器不支持可写连接

3 个答案:

1-您的上传表单或功能位于接收文件

2-秒选项，如果您的网络服务器与接收文件的服务器不同，则每个服务器上需要有两个文件：