以上代码旨在显示存储在sql表中的信息。一切都对应于表格中的标题和正确的顺序。但它所来自的页面只显示前两列,而不是其他列。一切看起来好像是为了我。我的陈述是错的?
<?php
$con=mysqli_connect("xxx","y","y","yyyy");
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$result = mysqli_query($con,"SELECT * FROM tripdata ");
while($row = mysqli_fetch_array($result))
{
echo $row['trip_id'] . " " . $row['image'] . " " . $row['date'] . " " . $row['destination'] . " " . $row['hl'] . " " . $row['cost'] . " " . $row['blurb'] . " " . $row['whatinc'] . " " . $row['whatopt'] . " " . $row['itin'] . " " . $row['depinfo'] . " " . $row['ppcode'];
echo "<br>";
}
mysqli_close($con);
?>
答案 0 :(得分:1)
也许你可以尝试使用assoc
while($row = mysqli_fetch_assoc($result))
{
echo $row['trip_id'] . " " . $row['image'] . " " . $row['date'] . " " . $row['destination'] . " " . $row['hl'] . " " . $row['cost'] . " " . $row['blurb'] . " " . $row['whatinc'] . " " . $row['whatopt'] . " " . $row['itin'] . " " . $row['depinfo'] . " " . $row['ppcode'];
echo "<br>";
}
我通常使用这个并没有问题
assoc是基于字段名称的索引名称 但是数组基于数字(0,1,2,3)
答案 1 :(得分:0)
奇怪。请尝试循环:
do {
echo $row['trip_id'] . " " . $row['image'] . " " . $row['date'] . " " . $row['destination'] . " " . $row['hl'] . " " . $row['cost'] . " " . $row['blurb'] . " " . $row['whatinc'] . " " . $row['whatopt'] . " " . $row['itin'] . " " . $row['depinfo'] . " " . $row['ppcode'];
echo "<br>";
} while($row = mysqli_fetch_array($result));