Question

我想从数据库中读取数据，并将其放在多维数组中。我不知道将来自数据库的行数，当我尝试向多维数组添加新行时，我有以下错误

Warning: array_push() [function.array-push]: First argument should be an array in C:\AppServ\www\web\commands\changeservice.php on line 101

这是我的代码

function preparenewservices()
    {

                $managername = $_SESSION['managername'];

                $sqls = "select s.*,m.* from rm_allowedmanagers m inner join rm_services s on s.srvid = m.srvid where m.managername = '$managername' ";


                $sql = mysql_query($sqls);


                 $newservices =  array();


                    while($row = mysql_fetch_array($sql))
                  {
                        $nsrvid = $row['srvid'];
                        $nsrvname = $row['srvname'];                        
                        $nunitprice = $row['unitprice'];
                        $nunitpricetax = $row['unitpricetax'];

                        $ntotal = $nunitprice + $nunitpricetax;

                        $newservice = array($nsrvid, $nsrvname , $ntotal); 

                        array_push ($newservices[count($newservices)], $newservice);

               }

    }

Answer 1

试试这个：

array_push ($newservices, $newservice);

而不是：

array_push ($newservices[count($newservices)], $newservice);

因为现在您传递给array_push integer值的第一个参数而不是array

Answer 2

多数民众赞成因为$newservices[count($newservices)]不是数组

在此处阅读文档array_push

只是为了解决错误，你可以做到这一点

$newservices[count($newservices)] = array();
array_push ($newservices[count($newservices)], $newservice);

Answer 3

尝试替换此代码

array_push（$ newservices [count（$ newservices）]，$ newservice）;

带

$ newservices [count（$ newservices）] = $ newservice;

Answer 4

将元素/数组添加到另一个数组的最简单方法是：

$newservices[] = $newservice;

在php中向多维数组添加数据时出错

4 个答案: