Android中的AsyncTask

Question

我想为此任务使用相同的套接字地址进行多次调用。

我试图从不同的班级获得地址，但没有工作。

请帮助!!!

我来自不同班级的电话是：

new ConnectToServer().execute(ip, "2000", "br1");

我的任务代码是：

public class ConnectToServer extends AsyncTask<String, Void, Void> {

    @Override
    protected Void doInBackground(String... parms) {
        // TODO Auto-generated method stub
        try {

            Socket s = new Socket(parms[0], Integer.parseInt(parms[1]));
            // ******

            OutputStream os = s.getOutputStream();
            BufferedOutputStream out = new BufferedOutputStream(os);

            if (parms[2] == "br1") {
                out.write("rr1".getBytes());
                out.write('\n');
                out.flush();
            } else if (parms[2] == "br2") {

                out.write("rr2".getBytes());
                out.write('\n');
                out.flush();
            } else if (parms[2] == "br3") {
                out.write("rr3".getBytes());
                out.write('\n');
                out.flush();
            } else if (parms[2] == "br4") {
                out.write("rr4".getBytes());
                out.write('\n');
                out.flush();
            } else if (parms[2] == "bb1") {
                out.write("bb1".getBytes());
                out.write('\n');
                out.flush();
            } else if (parms[2] == "bb2") {
                out.write("bb2".getBytes());
                out.write('\n');
                out.flush();
            } else if (parms[2] == "bb3") {
                out.write("bb3".getBytes());
                out.write('\n');
                out.flush();
            } else if (parms[2] == "bb4") {
                out.write("bb4".getBytes());
                out.write('\n');
                out.flush();
            }

            // s.shutdownOutput();

        } catch (NumberFormatException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        } catch (UnknownHostException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        } catch (IOException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }
        return null;
    }

}

Answer 1

您无法将java String与String == String进行比较。您需要改为使用String.equals(String)。

试试这段代码：

        if (parms[2].equals("br1")) {
            out.write("rr1".getBytes());
            out.write('\n');
            out.flush();
        } else if (parms[2].equals("br2")) {

            out.write("rr2".getBytes());
            out.write('\n');
            out.flush();
        } else if (parms[2].equals("br3")) {
            out.write("rr3".getBytes());
            out.write('\n');
            out.flush();
        } else if (parms[2].equals("br4")) {
            out.write("rr4".getBytes());
            out.write('\n');
            out.flush();
        } else if (parms[2].equals("bb1")) {
            out.write("bb1".getBytes());
            out.write('\n');
            out.flush();
        } else if (parms[2].equals("bb2")) {
            out.write("bb2".getBytes());
            out.write('\n');
            out.flush();
        } else if (parms[2].equals("bb3")) {
            out.write("bb3".getBytes());
            out.write('\n');
            out.flush();
        } else if (parms[2].equals("bb4")) {
            out.write("bb4".getBytes());
            out.write('\n');
            out.flush();
        }