Question

我开发了一个flash和php应用程序..

我希望从flash上传音频到php .. [bytearray data]

var ogg_data_bytes:ByteArray = _oggManager.encodedBytes;
var request:URLRequest = new URLRequest ('http://ravialla.com/uploads/save.php?filename=myFileName');
var loader: URLLoader = new URLLoader();
request.contentType = 'application/octet-stream';
request.method = URLRequestMethod.POST;
request.data = ogg_data_bytes;
loader.addEventListener(ProgressEvent.PROGRESS, uploadProgress);
loader.addEventListener(Event.COMPLETE, fileUploadSuccess);
loader.addEventListener(IOErrorEvent.IO_ERROR, fileUploadFaild);
loader.load(request);

现在我通过$ _GET传递文件名..但我希望通过$ _POST传递文件名

任何想法???

感谢：）

Answer 1

你能试试吗，

 var loader : URLLoader = new URLLoader();  
var request:URLRequest = new URLRequest ('http://ravialla.com/uploads/save.php');

request.method = URLRequestMethod.POST;  
var variables : URLVariables = new URLVariables();  
variables.key1 = myFileName;  
variables.key2 = "value2";  
request.data = variables;  

//  Handlers  
loader.addEventListener(Event.COMPLETE, on_complete);  
loader.load(request);  
private function on_complete(e : Event):void{  
       // whatever 
 }

参考：http://scriptcult.com/archives_9/article_442-post-request-data-in-as3.htm

$ GLOBALS ['HTTP_RAW_POST_DATA'] POST文件名

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