Question

我正在为我正在处理的工具制作一个“排行榜”，我需要将一些数字拉到一起并获得多行记录的数量。

您将在此存储过程中看到的是我尝试按2列的总和对记录进行排序。

有关如何完成此任务的任何提示？

AS
BEGIN
SET NOCOUNT ON;
        BEGIN
            SELECT DISTINCT(whoAdded),
                    count(tag) as totalTags,
                    count(DISTINCT data) as totalSubmissions
            FROM   Tags_Accounts
            GROUP BY whoAdded
            ORDER BY SUM(totalTags + totalSubmissions) DESC
            FOR    XML PATH ('leaderboard'), TYPE, ELEMENTS, ROOT ('root');
        END 
END

Answer 1

您可以通过将其放在派生表中来实现此目的：

SELECT *
FROM (
    SELECT DISTINCT(whoAdded) AS whoAdded,
        count(tag) as totalTags,
        count(DISTINCT data) as totalSubmissions
    FROM   Tags_Accounts
    GROUP BY whoAdded
    ) a
ORDER BY totalTags + totalSubmissions DESC
FOR    XML PATH ('leaderboard'), TYPE, ELEMENTS, ROOT ('root')

或者，你可以通过聚合来订购，但我认为上面的内容更清晰/更少：

SELECT DISTINCT(whoAdded) as whoAdded,
    count(tag) as totalTags,
    count(DISTINCT data) as totalSubmissions
FROM   Tags_Accounts
GROUP BY whoAdded
ORDER BY SUM(count(tag) + count(DISTINCT data)) DESC
FOR    XML PATH ('leaderboard'), TYPE, ELEMENTS, ROOT ('root')

Answer 2

SET NOCOUNT ON;
        BEGIN
            ;WITH CTE AS(
            SELECT DISTINCT(whoAdded),
                    count(tag) as totalTags,
                    count(DISTINCT data) as totalSubmissions
            FROM   Tags_Accounts
            GROUP BY whoAdded)
            SELECT * FROM CTE
            ORDER BY SUM(totalTags + totalSubmissions) DESC
            FOR    XML PATH ('leaderboard'), TYPE, ELEMENTS, ROOT ('root');
        END 
END

Answer 3

不要使用SUM()，只需使用+添加值，只使用表达式而不是列别名：

ORDER BY count(*) + count(DISTINCT data) DESC

SQL Count / sum in order子句

3 个答案: