Question

如果我不使用函数，我的代码工作正常。

declare function local:samlefamily(
$pers as xs:string?) as xs:string?
{
some stuff
};

if (exists(/*/FamilyRec/Child/Link[@Ref = "IN0099"])) 
then 
  for $family in doc("family.xml") /*/FamilyRec
  where $family/Child/Link[@Ref = "IN0099"]
  return if (local:samlefamily(data($family/HusbFath/Link/@Ref))) then local:samlefamily(data($family/HusbFath/Link/@Ref)) else "na1"  
else "na2"

但是当我尝试定义函数

时会出现问题

declare function local:giveParent($pers as xs:string) as xs:string
{if (exists(/*/FamilyRec/Child/Link[@Ref = $pers])) 
then 
  for $family in doc("gedcom.xml") /*/FamilyRec
  where $family/Child/Link[@Ref = $pers]
  return if (local:samlefamily(data($family/HusbFath/Link/@Ref))) then local:samlefamily(data($family/HusbFath/Link/@Ref)) else "na1"  
else "na2"
};

我收到错误：描述：意外的标记“＆lt; eof＆gt;”在路径表达式

传递参数（$ pers）不会发生。即使我使用静态（“IN0099”）参数，我得到同样的错误。有人可以帮忙吗？我不能在用户定义的函数中使用If ... else吗？高级感谢您的支持

Answer 1

你需要在xquery文件中至少有一个非函数语句，即在最后一个分号后添加任何内容

否则您的代码看起来很好

用户定义的xquery if else条件的函数

1 个答案: