所以我的代码适用于某些单词而不是其他单词,它会冲出字符串索引超出范围:-1 我想在每个元音和元音簇之前打印出ub 前可疑将是dubububious或cat loveo将是lubovudeo
String sentance,set;
sentance = "toster iooppp";
set= translate(sentance);
System.out.println(set);
}
public static String translate (String sentence){
String set = " ";
sentence= sentence.toLowerCase();
scan = new Scanner (sentence);
while (scan.hasNext()) {
set+= toUbbi (scan.next());
set += " ";
}
return set;
}
private static String toUbbi(String word ) {
String str= word;
String new_str="";
for (int i = 0; i < str.length(); i++) {
char c = str.charAt(i);
if (isVowel(c) && isVowel(str.charAt(i -1)) )
{ // If is a vowel
new_str += "ub" ;
}
new_str += c;
}
return new_str;
}
private static boolean isVowel(char c)
{
if (c == 'a' || c == 'e' || c == 'i' || c == 'o' || c == 'u' ){
return true;}
return false;
答案 0 :(得分:0)
在第一次迭代中它给出错误..
if (isVowel(c) && isVowel(str.charAt(i -1)) )
{ // If is a vowel
new_str += "ub" ;
}
所以这样改变..
if (isVowel(c))
{ // If is a vowel
new_str += "ub" ;
}
或改变你的循环..
for (int i = 1; i < str.length(); i++) {
// yur remain code...
}