我发现,MySql不支持连接中的相关查询。是否有可能重写提供的(简单的)查询保持逻辑?
SELECT *
FROM tableX AS x
LEFT JOIN (
SELECT y.xFK, COUNT(y.id) AS y_count
FROM tableY AS y
WHERE y.xFK = x.id
GROUP BY y.xFK
) AS sub
ON sub.xFK = x.id
WHERE sub.y_count > 1
提前致谢。
答案 0 :(得分:0)
这是你想要的吗?
SELECT
x.*, COUNT(y.ID) AS y_count
FROM tableX x
LEFT JOIN tableY y
ON y.xFK = x.ID
GROUP BY
x.ID
HAVING
y_count > 1