这是我尝试打开文件描述符并向其写入数据的代码。
#include <stdio.h>
#include <stdlib.h>
#include <fcntl.h>
#include <string.h>
#include <sys/stat.h>
#include <unistd.h>
void usage(char *prog_name,char *filename)
{
printf("Usage: %s <data to add to %s>\n", prog_name, filename);
exit(0);
}
void fatal(char *);
void *ec_malloc(unsigned int);
int main(int argc,char *argv[])
{
int fd;
char *buffer,*datafile;
buffer = (char*)ec_malloc(100);
datafile = (char*)ec_malloc(20);
strcpy(datafile,"/home/note");
if(argc<2)
usage(argv[0],datafile);
strcpy(buffer,argv[1]);
printf("[DEBUG] buffer@ %p: \'%s\'\n", buffer, buffer);
printf("[DEBUG] datafile @ %p: \'%s\'\n", datafile, datafile);
strncat(buffer,"\n",1);
fd = open(datafile,O_WRONLY|O_CREAT|O_APPEND,S_IRUSR|S_IWUSR);
if(fd = -1)
fatal("In main() while opening file\n");
printf("[DEBUG] file descriptor is %d\n", fd);
if(write(fd, buffer, strlen(buffer)) == -1)
fatal("in main() while writing buffer to file");
if(close(fd) == -1)
fatal("in main() while closing file");
printf("Note has been saved.\n");
free(buffer);
free(datafile);
}
void fatal(char *message){
char error_message[100];
strcpy(error_message,"[!!] Fatal Error ");
strncat(error_message,message,strlen(message));
perror(error_message);
exit(-1);
}
void *ec_malloc(unsigned int x){
void *ptr = malloc(x);
if(ptr == NULL)
fatal("in ec_malloc() on memory allocation");
return ptr;
}
现在如果我不给任何CL参数,那么响应是
Usage: ./simplenote <data to add to /tmp/note>
但是如果我给出命令行,例如,./simplenote "This is a test"
,则不返回filedescriptor。这是我得到的输出,
[DEBUG] buffer@ 0x1edf010: 'this is a test note'
[DEBUG] datafile @ 0x1edf080: '/tmp/note'
[!!] Fatal Error In main() while opening file
: Success
那么,问题是什么?为什么不能打开文件?
答案 0 :(得分:4)
if(fd = -1)
这是一个赋值,并且总是产生一个不等于零的值,因此总是输入if
的正文。
答案 1 :(得分:3)
if(fd = -1)
应为if(fd == -1)
答案 2 :(得分:1)
if(fd = -1)
应为if(fd == -1)
,如果您想避免此类错误,可以随时执行“YODA技巧”:
写:if(-1 == fd)
而不是if(fd == -1)
。它是一样的,但是如果你犯了错误if(-1 = fd)
,它将抛出一个编译错误!