我有这样的回答如何解析这些数据?任何建议
{ “响应”:[{ “作业ID”: “29”, “消息”: “egfn”, “lattitude”: “26.9514731”, “经度”: “89.4524783”, “job_status”: “P”, “日期”:“2013年11月21日 三点33分34" 秒, “用户名”: “用户”},{ “JOB_ID”: “28”, “消息”: “egfn”, “lattitude”: “26.9514731”, “经度”: “89.4524783”,” job_status “:” P “ ”日期“:” 2013年11月21日 三点33分34" 秒, “用户名”: “拉杰夫”},{ “JOB_ID”: “27”, “消息”: “egfn”, “lattitude”: “26.9514731”, “经度”: “89.4524783”,” job_status “:” P “ ”日期“:” 2013年11月21日 03:33:34“,”“username”:“pankaj”},{“job_id”:“26”,“message”:“测试工作为 你 “ ”lattitude“: ”25.4558641“, ”东经“: ”80.1325838“, ”job_status“: ”P“, ”日期“:” 2013年11月21日 01:09:58“,”username“:”users“},{”job_id“:”24“,”message“:”test job for 你 “ ”lattitude“: ”25.4558641“, ”东经“: ”80.1325838“, ”job_status“: ”d“, ”日期“:” 2013年11月21日 01:09:58“,”“username”:“amit”},{“job_id”:“25”,“message”:“测试工作为 你 “ ”lattitude“: ”25.4558641“, ”东经“: ”80.1325838“, ”job_status“: ”P“, ”日期“:” 2013年11月21日 1点09分58" 秒, “用户名”: “测试”}]}
提前致谢
答案 0 :(得分:1)
你可以这样做:
JSON.parse('{"response":[{"job_id":"29","message":"egfn","lattitude":"26.9514731","longitude":"89.4524783","job_status":"P","date":"2013-11-21 03:33:34","username":"users"},{"job_id":"28","message":"egfn","lattitude":"26.9514731","longitude":"89.4524783","job_status":"P","date":"2013-11-21 03:33:34","username":"rajeev"},{"job_id":"27","message":"egfn","lattitude":"26.9514731","longitude":"89.4524783","job_status":"P","date":"2013-11-21 03:33:34","username":"pankaj"},{"job_id":"26","message":"test job for you","lattitude":"25.4558641","longitude":"80.1325838","job_status":"P","date":"2013-11-21 01:09:58","username":"users"},{"job_id":"24","message":"test job for you","lattitude":"25.4558641","longitude":"80.1325838","job_status":"D","date":"2013-11-21 01:09:58","username":"amit"},{"job_id":"25","message":"test job for you","lattitude":"25.4558641","longitude":"80.1325838","job_status":"P","date":"2013-11-21 01:09:58","username":"test"}]}')
编辑:
获取所有job_id执行此操作:
var obj = JSON.parse('{"response":[{"job_id":"29","message":"egfn","lattitude":"26.9514731","longitude":"89.4524783","job_status":"P","date":"2013-11-21 03:33:34","username":"users"},{"job_id":"28","message":"egfn","lattitude":"26.9514731","longitude":"89.4524783","job_status":"P","date":"2013-11-21 03:33:34","username":"rajeev"},{"job_id":"27","message":"egfn","lattitude":"26.9514731","longitude":"89.4524783","job_status":"P","date":"2013-11-21 03:33:34","username":"pankaj"},{"job_id":"26","message":"test job for you","lattitude":"25.4558641","longitude":"80.1325838","job_status":"P","date":"2013-11-21 01:09:58","username":"users"},{"job_id":"24","message":"test job for you","lattitude":"25.4558641","longitude":"80.1325838","job_status":"D","date":"2013-11-21 01:09:58","username":"amit"},{"job_id":"25","message":"test job for you","lattitude":"25.4558641","longitude":"80.1325838","job_status":"P","date":"2013-11-21 01:09:58","username":"test"}]}')
var job_id_array = new Array();
for(var i = 0;i< obj.response.length ; i++){
job_id_array.push(obj.response[i].job_id);
}
答案 1 :(得分:1)
您可以使用JQuery.parseJSON()
答案 2 :(得分:1)
如果您的JSON字符串存储在json
变量中,您可以执行以下操作(假设环境支持ECMAScript5):
var o = JSON.parse(json);
var result=[];
o.response.forEach(function(e){
result.push(e.job_id);
});
console.log(result);
输出result
数组的内容:
["29", "28", "27", "26", "24", "25"]
这是一个解决您问题的live demo和good answer。