Question

我有这样的数组

Array ([0] => 
    Array (
       [user_id] => 21 
       [email] => momod@modara.com 
       [brand] => Array ( [0] => GOFUEL_W [1] => GOFUEL_USD_W ) ) 
      [1] =>
    Array (
       [user_id] => 22
       [email] => hemisphere@modara.com
       [brand] => Array ( [0] => GOFUEL_W ) )
      [2] =>
    Array (
       [user_id] => 23
       [email] => madoka@modara.com
       [brand] => Array ( [0] => GOFUEL_W [1] => GOFUEL_USD_W [2] => GOFUEL_BGD_W ) ) )

我想找到user_id 22并将此值“GO_FUEL_SGD_W”放在品牌上，我应该怎么做，所以数组的视图将如下所示

Array ([0] => 
    Array (
       [user_id] => 21 
       [email] => momod@modara.com 
       [brand] => Array ( [0] => GOFUEL_W [1] => GOFUEL_USD_W ) ) 
      [1] =>
    Array (
       [user_id] => 22
       [email] => hemisphere@modara.com
       [brand] => Array ( [0] => GOFUEL_W => [1] =>GO_FUEL_SGD_W ) )
      [2] =>
    Array (
       [user_id] => 23
       [email] => madoka@modara.com
       [brand] => Array ( [0] => GOFUEL_W [1] => GOFUEL_USD_W [2] => GOFUEL_BGD_W ) ) )

Answer 1

一个简单的foreach循环将完成这项工作：

foreach($myarray AS &$subarray) {
    if($subarray['user_id'] == 22) {
        $subarray['brand'][] = "GO_FUEL_SGD_W";
        break;
    }
}

工作示例：http://3v4l.org/8aQMj

Answer 2

只需使用循环：

foreach($array as &$item)
{
   if(array_key_exists('user_id', $item) && 
      $item['user_id']==22 &&
      array_key_exists('brand', $item) && 
      !in_array('GO_FUEL_SGD_W', $item['brand']))
   {
      $item['brand'][] = 'GO_FUEL_SGD_W';
   }
}

Answer 3

您需要迭代数组并查找您正在搜索的元素。

foreach ($array as &$element) {
    if ($element['user_id'] != 22)
        continue;

    $element['brand'][] = "GO_FUEL_SGD_W";
    break;
}

使用continue;将跳过所有元素，其中$element['user_id'] != 22（continue;之后的所有代码都将被应用于它们！）。

由于break;，一旦达到并修改了请求的元素，它也将结束循环。

Answer 4

$array= //your array;
foreach($array as $x){
    if($x['user_id']=='22'){
      $x['brand'][]='GO_FUEL_SGD_W';
      break;
    }

}

php在多维数组中的特定位置添加一些值

4 个答案: