Question

所以我试图使用依赖于用户输入的if-else语句。当用户的输入只有一个单词时，它可以工作，但是，多个单词输入无法识别并触发else语句。我怎么解决这个问题？

import java.util.Scanner;

public class MyFirstJavaClass {

public static void main(String[] args) {
    @SuppressWarnings("resource")
    Scanner myScanner = new Scanner(System.in);
    String answer;
    System.out.println("Catch the tiger or run away?");
    answer = myScanner.next();


         if (answer.equals("Catch the tiger"  )) {
            System.out.println("You've been mauled by a tiger! What were you thinking?");
            answer = myScanner.next();          

    } else {
        System.out.println("run away");
    }
  }
}

Answer 1

替换：

answer = myScanner.next();

使用：

answer = myScanner.nextLine();

接下来只会读取下一个值，直到它到达空格或换行符。在进行比较之前，您想要在整行中阅读

Answer 2

试试这个：

Scanner scanner = new Scanner(System.in);
int choice = 0;
while (scanner.hasNext()){
    if (scanner.hasNextInt()){
        choice = scanner.nextInt();
        break;
    } else {
        scanner.next(); // Just discard this, not interested...
    }
}

参考： Flush/Clear System.in (stdin) before reading

Answer 3

试试这个

import java.util.Scanner;

public class MyFirstJavaClass {

    public static void main(String[] args) {
        @SuppressWarnings("resource")
        Scanner myScanner = new Scanner(System.in);
        System.out.println("Catch the tiger or run away?");
        if (myScanner.hasNext("Catch the tiger")) {
            System.out.println("You've been mauled by a tiger! What were you thinking?");
        } else {
            System.out.println("run away");
        }
    }
}

java中的多字扫描输入？

3 个答案: