Question

嗨，我在这里有新的PHP，所以我需要一个帮助人我有一个输入和2个选择选项我想要----如果输入为空，则两个选择也是空的如果输入有一些值而不是第一个选择值应该是'打开'并且第二个选择值应该是'形式分发'像这样，这里两个选择都工作正常，但没有输入字段跟随任何帮助将gratfull谢谢你

           <!DOCTYPE html>
            <html>
            <head>
            <script type="text/javascript">
                function configureDropDownLists(ddl1,ddl2) {
                    var Open = new Array('Form Distributed');
                    var Completed = new Array('Ready for billing', 'Completed');
                    var Pending = new Array('With CS', 'With O&M (Estimate)', 'With Delegate','With Executive Engineer','With Consumer (Payment)','With O&M (Connection)');
                    var Rejected = new Array('Rejected: By CS', 'Rejected: By O&M', 'Rejected: By Delegate','Rejected: By EE','Rejected: Demand Expired','Rejected: By O&M');

                    switch (ddl1.value) {
                        case 'Open':
                            document.getElementById(ddl2).options.length = 0;
                            for (i = 0; i < Open.length; i++) {
                                createOption(document.getElementById(ddl2), Open[i], Open[i]);
                            }
                            break;
                        case 'Completed':
                            document.getElementById(ddl2).options.length = 0; 
                        for (i = 0; i < Completed.length; i++) {
                            createOption(document.getElementById(ddl2), Completed[i], Completed[i]);
                            }
                            break;
                        case 'Pending':
                            document.getElementById(ddl2).options.length = 0;
                            for (i = 0; i < Pending.length; i++) {
                                createOption(document.getElementById(ddl2), Pending[i], Pending[i]);
                            }
                            break;
                        case 'Rejected':
                            document.getElementById(ddl2).options.length = 0;
                            for (i = 0; i < Rejected.length; i++) {
                                createOption(document.getElementById(ddl2), Rejected[i], Rejected[i]);
                            }
                            break;
                            default:
                                document.getElementById(ddl2).options.length = 0;
                            break;
                    }

                }

                function createOption(ddl, text, value) {
                    var opt = document.createElement('option');
                    opt.value = value;
                    opt.text = text;
                    ddl.options.add(opt);
                }

            </script>
            </head>
            <input type="text" name="date" id="datepicker">
            <select id="ddl" onChange="configureDropDownLists(this,'ddl2')">
            <option value="0" ></option>
            <option value="Open">Open</option>
            <option value="Completed">Completed</option>
            <option value="Pending">Pending</option>
            <option value="Rejected">Rejected</option>
            </select>

            <select id="ddl2">
            </select>



            </body>
                </html>

Answer 1

（文档）$。就绪（函数（）{

changeInput();
$("#datepicker").change(function(){
    changeInput();
});

}）;

var options = ['Open'，'Completed'，'Pending'，'Rejected']; 功能改变输入（）{

var input = $("#datepicker").val();

var ddl = document.getElementById("ddl");
ddl.options.length = 0;
document.getElementById("ddl2").options.length = 0;

if(input==""){


}else{

    $.each(optios,function(){
        var opt = document.createElement('option');
        opt.value = this;
        opt.text = this;
        ddl.options.add(opt);
    });
    $("#ddl").val("Open");
    configureDropDownLists(ddl,'ddl2');
}

}

如何在java脚本中填充2选择一个选择？

1 个答案: