我有2个单独的表映射到SharedThing和TeamMember。
我有以下命名查询;
SELECT sharedThing
FROM SharedThing sharedThing,
TeamMember teamMember
WHERE teamMember.sharedId = sharedThing.sharedId
AND teamMember.userId = :userId
所以我将userId作为参数传递。
如何将相同的内容转换为本机sql查询?
答案 0 :(得分:1)
假设shared_thing
表映射到SharedThing
实体,而team_member
映射到TeamMember
:
SELECT st.*
FROM shared_thing st
JOIN team_member tm on tm.shared_id = st.id and tm.user_id = ?1
答案 1 :(得分:0)
使用join
语法和*
选择表格的所有列
select s.*
from SharedThing s
inner join TeamMember t on t.sharedId = s.sharedId
where t.userId = 123