如果你向下看主函数,错误就在于第一个输入。 当我输入\ q时,我的程序不会像我希望的那样终止。
任何人都可以向我解释为什么会发生这种情况吗?
我注意到如果我将fgets更改为scanf,那么\ q部分工作正常,但是然后(使用scanf)我的输入在空格后终止,如果我输入带有任何空格的字符串。
#include <stdio.h>
#include <cstring>
#include <ctype.h>
int count(char *input, char c) {
int k = strlen(input);
return 0;
}
void subanagram() {
char yes[50] = "yes";
char no [50] = "no";
char play[100];
char sa[100];
char strin[100];
char quitt[75] = { '/', 'q', '\0'};
do {
printf("Would you like to play the sub-anagram game?");
//scanf("%s", play);
fgets(play, 100, stdin);
if(stricmp(play, yes) == 0) {
printf("Enter a potential sub-anagram (or /q to quit): ");
scanf("%s", sa);
if(stricmp(sa, quitt) == 0) {
break;
}
}
}
while (stricmp(yes, play) == 0 || stricmp(no, play) == 0);
}
void main() {
char string[100];
char pally[75];
char nospace[100];
char reversed[100];
char yes[75] = {'y', 'e', 's', '\0'};
char quit[75] = { '\\', 'q', '\0'};
char no[75] = {'n', 'o', '\0'};
char play[50];
int p, i, k, j=0;
printf("Enter a word or phrase (or \\q to quit): ");
fgets(string, 100, stdin);
//scanf("%s", string);
k = strlen(string);
if(stricmp(quit, string) == 0) {
printf("Thank you for using my program!\n");
return;
}
do {
printf("Would you like to see if the phrase is a palindrome?");
scanf("%s", pally);
} while (stricmp(yes, pally) == 1 || stricmp(no, pally) == 1);
if(stricmp(yes, pally) == 0) {
for(i=0; i<k; i++) {
if(!isspace(string[i]) == 1) {
nospace[j] = string[i];
nospace[j+1] = '\0';
j++;
}
}
strcpy(reversed, nospace);
strrev(reversed);
if(stricmp(nospace, reversed) == 0) {
printf("The phrase %s IS a palindrome.\n", string);
subanagram();
}
else { printf("The phrase %s IS NOT a palindrome.\n", string);
subanagram();
}
}
if(stricmp(pally, no) == 0) {
/* printf("Would you like to play the sub-anagram game?");
scanf("%s", play);
if(strcmp(play, yes) == 0) {
subanagram();
}*/
subanagram();
}
}
答案 0 :(得分:0)
{ '/', 'q',
"...(or /q to quit): "
主要是:
char quit[75] = { '\\', 'q',
你的问题是:
"When I type \q, my program does not"
答案 1 :(得分:0)
'\n'
(字符作为换行符)作为您输入的字符串将包含在fgets(stinrg, 100, stdin)
与scanf("%s", string)
不同的情况中。因此,退出字符串更改为char quit[] = "\\q\n"
或删除最后一个\n'
,确定必须是一种处理,例如您喜欢。