Question

SELECT *
FROM Customer 
INNER JOIN Ledger Entry on [No_] = [Customer No_]
WHERE No_ NOT IN ([Posting Date] between '2013-10-01' and '2013-10-31')

BETWEEN条件不起作用。

Answer 1

这不是not in的工作原理，您将No_看似客户的Id与Posting Date进行比较，这样做会失败。

我想你想要这样的东西：

SELECT *
FROM Customer c
inner join [Ledger Entry] le on c.[No_] = le.[Customer No_]
where c.[No_] not in (
                        select l.[Customer No_] 
                        from [Ledger Entry] l 
                        where  l.[Posting Date] between '2013-10-01' and '2013-10-31'
                     )

但是对于这样的查询，它应该简化为：

SELECT *
FROM 
Customer c
inner join [Ledger Entry] le on c.[No_] = le.[Customer No_]
where le.[Posting Date] < '2013-10-01' or le.[Posting Date] > '2013-10-31'

根本不使用not in和between

Answer 2

首先，您的日期应与另一个日期类型列进行比较。
其次，根据Aaron Bertrand，您应该避免使用BETWEEN作为日期，您可以通过文章了解他是对的。
所以，我建议你继续;

SELECT * FROM Customer 
inner join LedgerEntry 
on Customer.[No_] = LedgerEntry.[Customer No_] 
where LedgerEntry.[Posting Date] < '2013-10-01' and LedgerEntry.[Posting Date] > '2013-10-31'

使用NOT IN时，BETWEEN条件不起作用

2 个答案: