Question

一旦检查此图片，..并告诉我如何解决这个问题 enter image description here

但是当我运行它时，....这个响应我得到了consloe，...告诉我如何在Url中提供这些数据，...在tomcat的本地主机......

并且还会看到此链接以获取更多详细信息，.. How to Create a Restful service for a Huge JSON data using Java eclipse Tomcat7.0

Answer 1

您的导入声明是什么样的？我使用org.json。*

首先你需要把json字符串放到一个字符串中，用BufferedReader逐行读取它。

然后你应该

JSONObject jsonObject = new JSONObject(json);

其中json是您使用BufferedReader

读取时获得的字符串

以下是一个例子：

try {

        InputStream is = new URL(url).openStream();
        BufferedReader rd = new BufferedReader(
                    new InputStreamReader(is, Charset.forName("UTF-8")));
        try {
        String json = rd.readLine();
        } finally {
            rd.close();
        }
        }  catch (Exception e) {
            System.out.println(e.toString());
        } 

JSONObject obj = new JSONObject(json);

Answer 2

以下是如何在java中创建json字符串的更多示例：

public String createJSONArrayOfObjects() throws JSONException {
        JSONArray list = new JSONArray();
        JSONObject obj = new JSONObject();
        obj.put("name", "foo");
        obj.put("num", new Integer(100));
        obj.put("balance", new Double(1000.21));
        obj.put("is_vip", true);
        obj.put("nickname", "");
        list.put(obj);

        obj = new JSONObject();
        obj.put("name" , "foo too");
        obj.put("num", new Integer(200));
        obj.put("balance", new Double(2000.21));
        obj.put("is_vip", true);
        obj.put("nickname", "");
        list.put(obj);

        return list.toString();
    }

    public String mixingJSONArrayAndObjects() throws JSONException {
        JSONArray list1 = new JSONArray();
        list1.put("foo");
        list1.put(new Integer(100));
        list1.put(new Double(1000.21));

        JSONArray list2 = new JSONArray();
        list2.put(true);

        JSONObject obj = new JSONObject();
        obj.put("name", "foo");
        obj.put("num", new Integer(100));
        obj.put("balance", new Double(1000.21));
        obj.put("is_vip", true);
        obj.put("nickname", "");

        obj.put("list1", list1);
        obj.put("list2", list2);

        return obj.toString();
    }

    public String createJSONArray() throws JSONException {
        JSONArray list = new JSONArray();
        list.put("foo");
        list.put(100);
        list.put(1000.21);
        list.put(true);
        return list.toString();   
    }

   public void createJSONArrayFromString(String anArray) throws JSONException {
       JSONArray list = new JSONArray(anArray);
       for (int i = 0; i < list.length(); i++) {
           switch (i) {
               case 0:
                   System.out.println(i + " " + list.getString(i));
                   break;
               case 1:
                   System.out.println(i + " " + list.getInt(i));
                   break;
               case 2:
                   System.out.println(i + " " + list.getDouble(i));
                   break;
               case 3:
                   System.out.println(i + " " + list.getBoolean(i));
                   break;
           }
       }
   }

    public String createObject() throws JSONException {
        JSONObject obj = new JSONObject();
        obj.put("name", "foo");
        obj.put("num", new Integer(100));
        obj.put("balance", new Double(1000.21));
        obj.put("is_vip", true);
        obj.put("nickname", "");

        return obj.toString();
    }

JSON响应数据获取控制台我使用Java，Eclipse，Tomcat

2 个答案: