Question

我有这张桌子

 user_id       DATE                 start_time       end_time
 1234          11/16/2013           8.30             9.30
 1234          11/16/2013           9.30             10.30
 1234          11/16/2013           12.30            13.30
 1234          11/19/2013           8.30             9.30

我想按如下方式汇总数据，将时间段分组：

 user_id       DATE                 start_time       end_time
 1234          11/16/2013           8.30             10.30
 1234          11/16/2013           12.30            13.30
 1234          11/19/2013           8.30             9.30

我如何在MySQL中执行此操作？

Answer 1

可能的解决方案

SELECT user_id, date, MIN(start_time) start_time, MAX(end_time) end_time
  FROM
(
  SELECT user_id, date, start_time, end_time,
         @n := IF(@u = user_id AND @d = date AND CAST(@e AS TIME) = start_time, @n, @n + 1) rnum,
         @u := user_id, @d := date, @e := end_time
    FROM table1 CROSS JOIN (SELECT @n := 0, @u := NULL, @d := NULL, @e := NULL) i
   ORDER BY user_id, date, start_time, end_time
) q
 GROUP BY user_id, date, rnum

输出：

+---------+------------+------------+----------+
| user_id | date       | start_time | end_time |
+---------+------------+------------+----------+
|    1234 | 2013-11-16 | 08:30:00   | 10:30:00 |
|    1234 | 2013-11-16 | 12:30:00   | 13:30:00 |
|    1234 | 2013-11-19 | 08:30:00   | 09:30:00 |
+---------+------------+------------+----------+

这是 SQLFiddle 演示

使用GROUP BY或任何其他方法汇总mysql数据

1 个答案: