Question

希望你做得好！

我有这个PHP脚本，使用户能够搜索数据库中学生的未付款，

$fname="fname";
     $date="date";
     $class="class";
     $database=("mcl");
     mysql_connect("localhost","root","mcl");
     @mysql_select_db(mcl) or die( "Unable to select database");


   if(isset($_REQUEST['submit'])){
   $fname=$_POST['fname'];
$date=$_POST['date'];
$class=$_POST['class'];

$sql="SELECT           
        SUM(school_fee),SUM(trans_fee),SUM(edutrip_fee),SUM(reg_fee),
             SUM(food_fee),SUM(stationery_fee),SUM(uniform_fee),idnumber,
              edutrip_setting,stationery_setting,food_setting,uniform_setting,
              register_setting,trans_setting,fee_setting,SUM(sport_uniform),
             sport_setting,fname,class,date FROM payment_one
        WHERE fname like '%".$fname."%' AND class like '%".$class."%' AND date  
            like '%".$date."%'";

         <?php
while($res=mysql_fetch_array($q)){
?>

<tr>
    <td width="100"><?php echo $res['fname'];?></td>
     <td width="200"><?php echo $res['fee_setting']- $res['SUM(school_fee)'];?></td>
     <td width="100"><?php echo $res['trans_setting']- $res['SUM(trans_fee)'];?></td>
     <td width="200"><?php echo $res['stationery_setting']-  
     $res['SUM(stationery_fee)'];?></td>
     <td width="200"><?php echo $res['register_setting']- $res['SUM(reg_fee)'];?></td>
    <td width="10"><?php echo $res['food_setting']- $res['SUM(food_fee)'];?></td>
    <td width="10"><?php echo $res['uniform_setting']- $res['SUM(uniform_fee)'];?></td>
    <td width="10"><?php echo $res['edutrip_setting']-   
    $res['SUM(edutrip_fee)'];?>       
    </td>
    <td width="10"><?php echo $res['sport_setting']- $res['SUM(sport_uniform)'];?></td>
    <td width="30"><?php echo $res['class'];?></td>
    <td width="280" style="border-width:medium"><?php echo $res['date'];?></td>
</tr>

<?php }?>

这是一张表

       $num="create table payment_one
      (id int primary key NOT NULL AUTO_INCREMENT,
      fk_id varchar (10) NULL,
      idnumber varchar (10) NULL,
      fname varchar (50) NOT NULL,
      class varchar (15) NOT NULL,
      school_fee FLOAT(8,2),
      trans_fee FLOAT(8,2),
      stationery_fee FLOAT(8,2),
      reg_fee FLOAT(8,2),
      food_fee FLOAT(8,2),
      uniform_fee FLOAT(8,2),
      edutrip_fee FLOAT(8,2),
      edutrip_name varchar (20),
      fee_setting FLOAT(8,2) NOT NULL,
      uniform_setting FLOAT(8,2) NOT NULL,
      register_setting FLOAT(8,2) NOT NULL,
      food_setting FLOAT(8,2),
        edutrip_setting FLOAT(8,2) NOT NULL,
        stationery_setting FLOAT(8,2),
        trans_setting FLOAT(8,2) NOT NULL,
       sport_uniform FLOAT(8,2),
       sport_setting FLOAT(8,2) NOT NULL,
      date date NULL)";

一旦你看起来正确你可能会在“payment_one”表中找到设置字段，在这个字段中带有学生想要支付的实际金额，例子（fee_setting是100000），这意味着一旦我设定了这个金额，减去学生支付的学费。

所以我的重大问题是：

注意：未定义的索引：SUM（school_fee）

注意：我将SUM用于收集每个学生的所有相应付款，以便通过'fee_setting'减去，以便知道每个学生剩下多少钱。

请任何人都可以帮我删除这个笔记真的让我不开心。

Answer 1

我不确定我是否正确理解了模糊描述的问题，它来自于您在PHP代码中执行$res['SUM(school_fee)']时的情况？

您可能需要在SQL中进行别名（例如SELECT SUM(school_fee) AS sum_school_fees），这样您之后就可以访问$res['sum_school_fees']。

Answer 2

我认为访问它的干净方法是为这些结果创建别名：

SELECT           
  SUM(school_fee) AS school_fee, 
  SUM(trans_fee) AS trans_fee, 
  SUM(edutrip_fee) AS edutrip_fee, 
  SUM(reg_fee) AS reg_fee,
  SUM(food_fee) AS food_fee, 
  SUM(stationery_fee) AS stationary_fee, 
  SUM(uniform_fee) AS uniform_fee, ...

然后将其作为：

访问

$res['school_fee']

如何在这个PHP脚本中删除此未定义的索引

2 个答案: