Question

在IF语句中使用来自HttpClient的响应时遇到问题。我用它来验证登录的用户名和密码，这里是登录类

public class loginClass {
    public static String verify(EditText username, EditText password){
        String UN = username.getText().toString();
        String PW = password.getText().toString();

        String PWencrypt = Encrypt.md5(PW);
        HttpClient httpclient = new DefaultHttpClient();
        HttpPost httppost = new HttpPost("http://cstudios.co.uk/cstudiosApps/Login.php?UN="+UN+"&PW="+PWencrypt);
        try{
            // Execute HTTP Post Request
            BasicHttpResponse response = (BasicHttpResponse) httpclient.execute(httppost);
            String Val = EntityUtils.toString(response.getEntity());
            String[] Value = Val.split(",");
            if(Value[1] == "FAIL"){
                return "False";
            }else{
                String UserID = Value[1];
                return UserID;
            }
        } catch (ClientProtocolException e) {
            return "Error";
        } catch (IOException e) {
            return "Error";
        }
    }
}

以下是PHP文件的代码：

<?php
//Getting Username from APP
$UN = $_GET["UN"];
$UN = mysql_real_escape_string($UN);
$PW = $_GET["PW"];
// Create Connection
$con=mysqli_connect($URL,$username,$password,$Database);
// Check connection
if (mysqli_connect_errno($con))
{
    echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
//Login Query
$GetPW = mysqli_query($con,"SELECT * FROM users WHERE Username='$UN'");
while($row = mysqli_fetch_array($GetPW))
    {
        $PWtest=$row['Password'];
        $USERid=$row['UserID'];
    }
if($PW==$PWtest)
    {
        echo "," . $USERid . ",";//for use of APP
    }else{
        echo ',FAIL,';
    }
//Close Connection
mysqli_close($con);
?>

我设置了上面的Sql变量我只是不想粘贴它，对此的任何帮助都会很棒，使用时会出现问题

if(Value[1] == "FAIL")

因为它永远不会返回false ... 提前感谢您的帮助。

Answer 1

使用.equals（）方法比较java中的字符串。

Android HttpResponse无法在IF语句中使用来检查内容

1 个答案: