这是它应该打印的模式。这就是我现在所做的代码。每个数字之间应该有5个空格。有谁可以帮助我吗?
模式:
1
2 0 2
3 0 0 0 3
我的代码:
import java.util.Scanner;
public class Triangle{
public static void main(String args[]) {
System.out.println("Input the number of lines you want to print.");
Scanner a = new Scanner(System.in);
int n = a.nextInt();
int[] row = new int[0];
for(int i=0 ; i < n ; i++){
row = nextRow(row);
for(int j=0;j < n-i;j++){
//Padding For Triangle
System.out.print(" ");
}
//Output the values
for(int j=0 ; j < row.length ; j++){
System.out.print(row[j]+" ");
}
//Start New Line
System.out.println();
}
}
/*Find Values Of Next Row*/
public static int[] nextRow(int row[]){
int nextRow[] = new int [row.length+1];
nextRow[0] = row.length+1;
nextRow[nextRow.length-1] =row.length+1;
for(int i=1 ; i < nextRow.length-1 ; i++){
nextRow[i] = 0;
}
return nextRow;
}
}
答案 0 :(得分:0)
这是一些修改后的代码。它不完整,仍然需要更新您的代码以获得所需的结果。那部分我要留给你。我还在代码中留下了提示,以便您可以修改。
1.
// Padding For Triangle
System.out.print(" "); // 6 white space
2.
System.out.print(row[k]);
System.out.print(" "); // 5 white space
3.
/* Find Values Of Next Row */
@SuppressWarnings("null")
public static int[] nextRow(int row[]) {
int nextRow[] = null;
if (row.length == 0) {
nextRow = new int[1];
nextRow[0] = 1;
} else {
// count++; // Hint
nextRow = new int[row.length + 2];
for (int i = 0; i < nextRow.length; i++) {
if ((i == 0 || i == nextRow.length - 1)) {
nextRow[i] = nextRow.length - 2;
// nextRow[i] = count;
} else {
nextRow[i] = 0;
}
}
}
return nextRow;
}
如果您有任何疑问,请询问。祝你好运。
答案 1 :(得分:0)
首先必须确定输出所需的模式,在您的情况下是:
Row0, columns 1
Row1, columns 3
Row2, columns 5
Row3, columns 7
,即rowNum * 2 + 1
基于此,我修改了你的代码,这是工作解决方案:
import java.util.Scanner;
public class Triangle{
public static void main(String args[]) {
System.out.println("Input the number of lines you want to print.");
Scanner a = new Scanner(System.in);
int n = a.nextInt();
int[] row = null;
for(int i=0 ; i < n ; i++){
row = nextRow(i);
for(int j=0;j < n-i;j++){
//Padding For Triangle
System.out.print(" ");
}
//Output the values
for(int j=0 ; j < row.length ; j++){
System.out.print(row[j]+" ");
}
//Start New Line
System.out.println();
}
}
/*Find Values Of Next Row*/
public static int[] nextRow(int rowNum){
int nextRow[] = new int [rowNum*2+1];
nextRow[0] = rowNum+1;//-rowNum/2;
nextRow[nextRow.length-1] = nextRow[0];
for(int i=1 ; i < nextRow.length-1 ; i++){
nextRow[i] = 0;
}
return nextRow;
}
}
这是一些输出:
2:
1
2 0 2
5:
1
2 0 2
3 0 0 0 3
4 0 0 0 0 0 4
5 0 0 0 0 0 0 0 5
10:
1
2 0 2
3 0 0 0 3
4 0 0 0 0 0 4
5 0 0 0 0 0 0 0 5
6 0 0 0 0 0 0 0 0 0 6
7 0 0 0 0 0 0 0 0 0 0 0 7
8 0 0 0 0 0 0 0 0 0 0 0 0 0 8
9 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 9
10 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 10
答案 2 :(得分:-1)
我看到了你的代码,我认为我们可以这样做,以下是我修改过的代码:
public class Triangle {
public static void main(String args[]) {
System.out.println("Input the number of lines you want to print.");
Scanner a = new Scanner(System.in);
int n = a.nextInt();
int [] row = new int[0];
for (int i = 0; i < n; i++) {
row = nextRow(row);
for (int j = 0; j < n - i; j++) {
// Padding For Triangle
System.out.print(" ");
}
// Output the values
for (int j = 0; j < row.length; j++) {
System.out.print(row[j] + " ");
}
// Start New Line
System.out.println();
}
}
/* set space between each other. */
public static String printSpace(int n) {
String result = "";
for (int i = 0; i < n; i++) {
result += " ";// 5 space
}
return result;
}
/* Find Values Of Next Row */
public static int [] nextRow(int row[]) {
int nextRow[] = new int[row.length + 1];
nextRow[0] = row.length + 1;
nextRow[nextRow.length - 1] = row.length + 1;
for (int i = 1; i < nextRow.length - 1; i++) {
nextRow[i] = 0;
}
return nextRow;
}
}
可能是你想要的答案。
答案 3 :(得分:-2)
查找用于打印出零的算术序列,其余的应该是微不足道的。