我收到了这段代码,但是当地图加载时,我需要通过点击按钮隐藏并显示搜索结果,是否可以帮助?
代码:
var map;
var infowindow;
function initialize() {
var pyrmont = new google.maps.LatLng(-33.8665433, 151.1956316);
map = new google.maps.Map(document.getElementById('map-canvas'), {
center: pyrmont,
zoom: 15
});
var request = {
location: pyrmont,
radius: 500,
types: ['store']
};
infowindow = new google.maps.InfoWindow();
var service = new google.maps.places.PlacesService(map);
service.nearbySearch(request, callback);
}
function callback(results, status) {
if (status == google.maps.places.PlacesServiceStatus.OK) {
for (var i = 0; i < results.length; i++) {
createMarker(results[i]);
}
}
}
function createMarker(place) {
var placeLoc = place.geometry.location;
var marker = new google.maps.Marker({
map: map,
position: place.geometry.location
});
google.maps.event.addListener(marker, 'click', function() {
infowindow.setContent(place.name);
infowindow.open(map, this);
});
}
google.maps.event.addDomListener(window, 'load', initialize);\
修改
我尝试创建一个按钮,点击后显示谷歌地方的搜索结果..我隐藏了制造商,并向按钮显示标记的功能,但这不成功
function createMarker(place) {
var placeLoc = place.geometry.location;
var markersr = new google.maps.Marker({
map: map,
icon:icon2,
visible:false,
position: place.geometry.location,
});
功能
function showsearch() {
markersr.setVisible(true);
}
按钮
<input type="checkbox" name="btn2" onClick="showsearch()" class="btn2" >
答案 0 :(得分:1)
请参阅链接。 http://jsfiddle.net/y829C/1/
var mapOptions = {
center: new google.maps.LatLng(latitude, longitude),
zoom: 8,
mapTypeId: google.maps.MapTypeId.ROADMAP
};
<强>更新强>