Java套接字不接收数据

时间:2013-11-21 20:51:00

标签: java sockets

我必须编写服务器应用程序,从客户端请求问题并收到答案。这是我的客户代码:

clientSocket = new Socket("localhost", 1234);
        System.err.println("Client started");
//get questions
        ObjectInputStream in = new ObjectInputStream(clientSocket.getInputStream());
        Question q = (Question)in.readObject();
//send answer
        PrintWriter out = new PrintWriter(clientSocket.getOutputStream());
        out.print("a1");
        out.flush();

和服务器代码:

//sending questions
ObjectOutputStream out = new ObjectOutputStream(client.getOutputStream());
        List<Question> quest = Questions.getInstance().getQuestions();
        out.writeObject(quest.get(0));
        out.flush();
    //get answer
        BufferedReader in = new BufferedReader(new InputStreamReader(client.getInputStream()));
        String temp = null;
        while ((temp = in.readLine()) == null) {}
        String answer = temp;

客户端成功发送并稍后收到的问题,但服务器永远不会得到答案(读取临时变量时无限循环)。有什么问题?

1 个答案:

答案 0 :(得分:0)

  

你的呼唤out.print(“a1”);在客户端上,但使用in.readLine()在服务器上读取一行。你不应该在客户端上使用println()写出来,否则服务器永远不会到达行尾? - CodeChimp 11月21日21:07

感谢CodeChimp