Question

我有一个字典列表，如果2个键的值中的2个每个都有一个已定义的字符串，我想要过滤这些字典

例如，在下面的列表中过滤（A = BBB和D = EEE）......

[{A:BBB, C:DDD, D:EEE,...}, {A:BBB, C:DDD, D:ESS,...},{A:BBB, C:ASD, D:EEE,...},{C:ASD, D:EEE,...},...]

输出

[{A:BBB, C:DDD, D:EEE,...},{A:BBB, C:ASD, D:EEE,...},...]

任何帮助将不胜感激！

Answer 1

试试这个，它是一个使用列表推导的单行：

# input data
lst = [{'A':'BBB', 'C':'DDD', 'D':'EEE'},
       {'A':'BBB', 'C':'DDD', 'D':'ESS'},
       {'A':'BBB', 'C':'ASD', 'D':'EEE'},
       {'C':'ASD', 'D':'EEE'}]

# list of filters
flt = [('A', 'BBB'), ('D', 'EEE')]

# a list comprehension + all() will do the trick
[x for x in lst if all(x.get(k, None) == v for k, v in flt)]
=> [{'A': 'BBB', 'C': 'DDD', 'D': 'EEE'}, {'A': 'BBB', 'C': 'ASD', 'D': 'EEE'}]

这种方法的好处是你可以根据需要在过滤器中声明尽可能多的键/值对，无论如何它都可以工作。

Answer 2

result = []
for i in lst:
    if i['A'] == "BBB" and i['D'] == "EEE":
        result.append(i)

Answer 3

l = [{'A': 'BBB', 'C': 'DDD', 'D': 'EEE'}, {'A': 'BBB', 'C': 'DDD', 'D': 'ESS'},
    {'A': 'BBB', 'C': 'ASD', 'D': 'EEE'}, {'C': 'ASD', 'D': 'EEE'}]
filterd = {'D': 'EEE', 'A': 'BBB'}                                         
[x for x in l if x.viewvalues() >= filterd.viewvalues()]                   
[{'A': 'BBB', 'C': 'DDD', 'D': 'EEE'}, {'A': 'BBB', 'C': 'ASD', 'D': 'EEE'}]

Answer 4

output = [d for d in list_of_dicts
            if not (d['A'] == 'BBB' and d['D'] == 'EEE')]

按值过滤字典

4 个答案: