Question

在我的表courses中，我有几个共享相同academy_id值的条目。我使用foreach循环来检索具有相同academy_id的所有行。在下面的例子中，有一个学院有两门课程。值正确显示，但显示了一些不必要的值。例如，它会创建两个结果。是否可以在wanted result to display部分中显示如下所示的一个组合结果？

PHP

$academy_id = 123

$db_select  = $db_con->prepare("
SELECT ca.course_name,
       ca.course_start_date,
       ca.course_end_date
FROM courses_by_academy ca
WHERE ca.academy_id = :academy_id
");
$final_result = '';
if (!$db_select) return false;
    if (!$db_select->execute(array(':academy_id' => $academy_id))) return false;
    $results = $db_select->fetchAll(\PDO::FETCH_ASSOC);
    if (empty($results)) return false;
    foreach ($results as $value){
    $final_result .= "<b>Academy Name: </b>".$value['name']."</br><b>Academy Type: </b>".$value['type']."</br><b>Status: </b>".$value['status']."</br>";
    $final_result .= "<b>Course Name: </b>".$value['course_name']."</br><b>Start Date: </b>".$value['course_start_date']."</br><b>End Date: </b>".$value['course_end_date']."</br>";
    }
}

表值

+----+------------+----------------------+---------------+------------+
| id | academy_id |     course_name      |  start_date   |  end_date  |
+----+------------+----------------------+---------------+------------+
| 1  |        123 | Biology - Basic      | 2013-11-30    | 2013-12-25 |
| 2  |        123 | Biology - Nutrition  | 2014-01-15    | 2014-01-25 |
+----+------------+----------------------+---------------+------------+

显示当前结果

Academy Name: North Valley Schools
Academy Type: Post-Secondary
Status: INACTIVE
ID: 123
Course Name:  Biology - Basic  
Start date: 2013-11-30
End date: 2013-12-25

Academy Name: North Valley Schools
Academy Type: Post-Secondary
Status: INACTIVE
ID: 123
Course Name:  Biology - Nutrition 
Start date: 2014-01-15
End date: 2014-01

通缉结果 - 合并

Academy Name: North Valley Schools
Academy Type: Post-Secondary
Status: INACTIVE
ID: 123
Course Name:  Biology - Basic  
Start date: 2013-11-30
End date: 2013-12-25
Course Name:  Biology - Nutrition 
Start date: 2014-01-15
End date: 2014-01-25

Answer 1

你的循环：

foreach ($results as $value){
   $final_result .= "<b>Academy Name: </b>".$value['name']."</br><b>Academy Type: </b>".$value['type']."</br><b>Status: </b>".$value['status']."</br>";
    $final_result .= "<b>Course Name: </b>".$value['course_name']."</br><b>Start Date: </b>".$value['course_start_date']."</br><b>End Date: </b>".$value['course_end_date']."</br>";
}

代替：

$first = true;
foreach ($results as $value){
    if($first){
        $first = false;
        $final_result .= "<b>Academy Name: </b>".$value['name']."</br><b>Academy Type: </b>".$value['type']."</br><b>Status: </b>".$value['status']."</br>"; 
    }
    $final_result .= "<b>Course Name: </b>".$value['course_name']."</br><b>Start Date: </b>".$value['course_start_date']."</br><b>End Date: </b>".$value['course_end_date']."</br>";
}

它只会执行一次学院信息。：）

为每个循环显示来自mysql表的值

1 个答案: