Google自动填充API - 格式输出结果

时间:2013-11-21 15:00:23

标签: javascript jquery javascript-events google-places-api

我正在尝试实施Google Places API,因此这是我的代码:

<!DOCTYPE html>
<html>
<head>
    <script src="http://codeorigin.jquery.com/jquery-1.10.2.min.js"></script>
    <script src="//maps.googleapis.com/maps/api/js?v=3.exp&sensor=false&libraries=places&location=0,0&radius=20000000&language=de"></script>
    <script>
        $(document).ready(function() {
            var el = $('#street').attr("placeholder", "")
                    , autocomplete = new google.maps.places.Autocomplete( ( el.get(0) ), { types: ['geocode'] } );

            el.bind("blur", function() {
                // blur is triggered before place_changed, as well as focus... so this is not working as well
            })

            google.maps.event.addListener(autocomplete, 'place_changed', function() {
                var place = autocomplete.getPlace();

                el.val(place.name); // this line is not working well - still default content showing !!!
            });
        })
    </script>
</head>
<body">
    <input type="text" id="street" style="width:400px;" />
</body>
</html>

谷歌自动填充功能正常,但我有一个要求 - 只显示街道名称&amp;数字而不是Google建议的完整地址。所以我可以通过在“place_changed”事件中运行autocomplete.getPlace()来获取所有信息 - 这没有问题。

问题是我无法用我的自定义文本覆盖自动完成输入值 - 我试图在“模糊”,“焦点”,“place_changed”事件中执行此操作 - 仍然没有运气。请找一个我正在尝试的例子。此外 - 我需要避免文字闪烁,使其绝对用户友好。有人可以帮助我尝试吗?

JSFiddle:http://jsfiddle.net/8pGH2/

2 个答案:

答案 0 :(得分:1)

我能够使用以下代码解决我的问题:

$(document).ready(function() {
     var el = $('#street').attr("placeholder", "")
        , autocomplete = new google.maps.places.Autocomplete( ( el.get(0) ), { types: ['geocode'] } );

        el.bind("blur", function() {
          el.css("color", "#fff"); // this will prevent text flashing
        })

        google.maps.event.addListener(autocomplete, 'place_changed', function() {
           var place = autocomplete.getPlace();

            el.val(place.name);

            // this will override default Google suggestion
            setTimeout(function() {
                el.val(place.name);
                el.css("color", "");
            }, 0)
        });
})

答案 1 :(得分:0)

你可以通过

el.get(0).getLocality()