Question

在PHP中我使用过：

if($a=="no" or $curriculum=="yes")

您发现if声明有什么问题吗？

即使if和$a = yes，它也会显示$curriculum = no的内容。我已经做了足够的检查来检查变量是否具有正确的值。请帮忙!!

Answer 1

你可以试试这个

if($a=="no" || $curriculum=="yes")

Answer 2

好的，这是一些测试。你的if语句没问题（or和||在这种情况下一样）

$a = 'abc';
$curriculum = 'abc';
if($a == "no" or $curriculum == "yes") {
    echo 'Either $a equals "no" or $curriculum equals "yes"<br>'.PHP_EOL;
} else {
    echo 'Neither $a equals "no" nor does $curriculum equal "yes"<br>'.PHP_EOL;
}

$a = 'no';
$curriculum = 'abc';
if($a == "no" or $curriculum == "yes") {
    echo 'Either $a equals "no" or $curriculum equals "yes"<br>'.PHP_EOL;
} else {
    echo 'Neither $a equals "no" nor does $curriculum equal "yes"<br>'.PHP_EOL;
}

$a = 'abc';
$curriculum = 'yes';
if($a == "no" or $curriculum == "yes") {
    echo 'Either $a equals "no" or $curriculum equals "yes"<br>'.PHP_EOL;
} else {
    echo 'Neither $a equals "no" nor does $curriculum equal "yes"<br>'.PHP_EOL;
}

这导致：

Neither $a equals "no" nor does $curriculum equal "yes"
Either $a equals "no" or $curriculum equals "yes"
Either $a equals "no" or $curriculum equals "yes"

请在if语句之前对两个变量执行var_dump并向我们显示结果：

var_dump($a);
var_dump($curriculum);
if($a == "no" or $curriculum == "yes") {

如果声明在我的代码中不起作用。变量未经过测试

2 个答案: