Question

有这样的回应：

[{
        "pic_50" : "http://avt.appsmail.ru/mail/rogozina.zoya/_avatar50",
        "friends_count" : 41,
        "pic_hires_filed" : "http://content.foto.mail.ru/mail/rogozina.zoya/_myphoto/h-43.jpg",
        "nick" : "самвел",
        "is_friend" : 0,
        "is_online" : 1,
        "has_pic" : 1,
        "pic_190" : "http://avt.appsmail.ru/mail/rogozina.zoya/_avatar190",
        "referer_id" : "",
        "pic_32" : "http://avt.appsmail.ru/mail/rogozina.zoya/_avatar32",
        "referer_type" : "",
        "last_visit" : "1385039467",
        "location" : {
            "country" : {
                "name" : "Россия",
                "id" : "24"
            },
            "city" : {
                "name" : "Тюмень",
                "id" : "1553"
            },
            "region" : {
                "name" : "Тюменская обл.",
                "id" : "280"
            }
        },
        "uid" : "11070260334392665635",
        "app_installed" : 1,
        "status_text" : "",
        "pic_filed" : "http://content.foto.mail.ru/mail/rogozina.zoya/_myphoto/i-43.jpg",
        "pic_22" : "http://avt.appsmail.ru/mail/rogozina.zoya/_avatar22",
        "pic_id" : "43",
        "age" : 49,
        "last_name" : "Кочарян",
        "pic_big" : "http://avt.appsmail.ru/mail/rogozina.zoya/_avatarbig",
        "is_verified" : 1,
        "vip" : 0,
        "birthday" : "11.11.1964",
        "link" : "http://my.mail.ru/mail/rogozina.zoya/",
        "pic_128" : "http://avt.appsmail.ru/mail/rogozina.zoya/_avatar128",
        "sex" : 0,
        "pic_small" : "http://avt.appsmail.ru/mail/rogozina.zoya/_avatarsmall",
        "pic" : "http://avt.appsmail.ru/mail/rogozina.zoya/_avatar",
        "pic_180" : "http://avt.appsmail.ru/mail/rogozina.zoya/_avatar180",
        "first_name" : "Самвел",
        "pic_40" : "http://avt.appsmail.ru/mail/rogozina.zoya/_avatar40"
    }
]

如何反序列化？

Answer 1

使用Newtonsoft JSON.NET（可从NuGet获得）：

var array = (JArray)JsonConvert.DeserializeObject(json);
var obj = (JObject)array[0];
var pic180 = obj["pic_180"];

Answer 2

我投了其他答案（JSON.NET可能是大多数人的最佳选择），但我个人更喜欢

http://wiki.unity3d.com/index.php/SimpleJSON

作为解串器。它很简单，在一个文件中可以包含在您的项目中。如果您在格式中有一些非标准，您可以轻松调整它。

Answer 3

将Newtonsoft.Json库的引用添加到您的项目并尝试此代码

ClassName obj = JsonConvert.DeserializeObject<ClassName>(serializedJson);

如何反序化这样的json响应？

3 个答案: