Question

我的目标是

    String obj = " {\"userNames\":[\"aaaaa aaaaa\",\"Anders Ohm\",\"Arthur Hansen\"]}";

需要将obj转换为java List对象，其中包含带有元素的用户名的详细信息＆＃34; aaaaa aaaaa＆＃34;，＆＃34; Anders Ohm＆＃34;，＆＃34; Arthur Hansen＆＃34;

Answer 1

您可以使用jackson库进行json处理。

使用ObjectMapper，您的JSON可以像这样解析：

class Data {
    List<String> userNames = new ArrayList<>();

    public List<String> getUserNames() {
        return userNames;
    }

    public void setUserNames( List<String> userNames ) {
        this.userNames = userNames;
    }
}

public static void main( String[] args ) throws IOException
{
    String obj = " {\"userNames\":[\"aaaaa aaaaa\",\"Anders Ohm\",\"Arthur Hansen\"]}";

    ObjectMapper mapper = new ObjectMapper();
    Data data = mapper.readValue( obj, Data.class );

    System.out.println(data.getUserNames());
}

Answer 2

首先你需要创建类

public class UserNames {


    private List<String> userNames;

    public  List<String> getUserNames() {
        return userNames;
    }

    public  void setUserNames(List<String> userNames) {
        this.userNames = userNames;
    }
}

然后将其解析为

String obj = " {\"userNames\":[\"aaaaa aaaaa\",\"Anders Ohm\",\"Arthur Hansen\"]}";
        UserNames userNames =gson.fromJson(obj, UserNames.class);
        List<String> names = userNames.getUserNames();

您可以从此处下载Google gson

Gson

将json对象转换为java list对象

2 个答案: