我正在尝试显示我的数据库中的列名,我可以使用mysqli_fetch_field()
函数执行此操作,但我的问题是,当我只想输出每个列时,它会多次输出列名列名一次。我将$field_info
变量设置为该函数,该变量采用参数$result
,该参数设置为我的查询,所有这些都放入我的while循环中。我有一种感觉,这可能是由我的while循环引起的?但我不太确定。
$query = "SELECT * FROM bodyshops_master_network";
if ($result = $mysqli->query($query))
{
// print the column names as the headers of a table
while ($field_info = mysqli_fetch_field($result))
{
printf("postcodes_covered %s\n", $field_info->postcodes_covered);
printf("dealer_code %s\n", $field_info->dealer_code);
printf("dealer_name %s\n", $field_info->dealer_name);
printf("bodyshop_id %s\n", $field_info->bodyshop_id);
printf("bodyshop_name %s\n", $field_info->bodyshop_name);
printf("address1 %s\n", $field_info->address1);
printf("address2 %s\n", $field_info->address2);
printf("address3 %s\n", $field_info->address3);
printf("address4 %s\n", $field_info->address4);
printf("address5 %s\n", $field_info->address5);
printf("postcode %s\n", $field_info->postcode);
printf("BO_tel %s\n", $field_info->BO_tel);
printf("BO_email %s\n", $field_info->BO_email);
printf("BC_name %s\n", $field_info->BC_name);
printf("equity_contract %s\n", $field_info->equity_contract);
}
答案 0 :(得分:0)
尝试这种方式:
// making a query
$query = "SELECT * FROM bodyshops_master_network";
// firing a query and getting the resource in $result variable
$result = $mysqli->query($query);
$i = 0;
// loop all fields
while ($i < mysqli_field_count($result)) {
// fetching field information. Index of the field is given by $i
$meta = mysqli_fetch_field($result, $i);
// display information for each field here
.
.
//
$i++;
}
参考 mysqli_field_count 和 mysqli_fetch_field 官方文档