是否可以通过引用实体进行分组来选择JPA中的数据?
我的意思是:我有两个实体 - 保险和参考多对一车辆。保险实体有validTill字段(当然还有车辆字段)。
我想选择车辆,这是最新的保险。以下查询不起作用:
SELECT DISTINCT v.vehicle,
max(v.validTill) as lastValidTill
FROM TraInsurance v
GROUP BY v.vehicle
ORDER BY lastValidTill
上述查询失败,错误:
ERROR: column "travehicle1_.id_brand" must appear in the GROUP BY clause or be used in an aggregate function
这是因为JPA将引用车辆的所有字段添加到查询而不是GROUP BY。这是我做错了吗?或者也许只是不可能这样做?
修改
TraInsurance实体
@Entity
@Table(name = "TRA_INSURANCES", schema="public")
@SequenceGenerator(name = "TRA_INSURANCES_SEQ", sequenceName = "TRA_INSURANCES_SEQ", allocationSize = 1)
public class TraInsurance implements EntityInt, Serializable {
private static final long serialVersionUID = 1L;
@Id
@Column(name = "id", nullable = false)
@GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "TRA_INSURANCES_SEQ")
private Long id;
@NotNull
@ManyToOne
@JoinColumn(nullable = false, name = "id_vehicle")
private TraVehicle vehicle;
@NotNull
@Column(name = "valid_from", nullable = false)
private Date validFrom;
@Column(name = "valid_till", nullable = false)
private Date validTill;
@NotNull
@ManyToOne
@JoinColumn(nullable = false, name = "id_company")
private Company company;
@Column(name = "policy_no", nullable = true, length = 50)
private String policyNumber;
@Column(name = "rate", nullable = true, precision = 12, scale = 2)
private BigDecimal rate;
@Column(name = "discount_percent", nullable = true)
private Float discountPercent;
@Column(nullable = true)
private String description;
public TraInsurance() {}
public Long getId() {
return id;
}
public void setId(Long id) {
this.id = id;
}
public TraVehicle getVehicle() {
return vehicle;
}
public void setVehicle(TraVehicle vehicle) {
this.vehicle = vehicle;
}
public Date getValidFrom() {
return validFrom;
}
public void setValidFrom(Date validFrom) {
this.validFrom = validFrom;
}
public Date getValidTill() {
return validTill;
}
public void setValidTill(Date validTill) {
this.validTill = validTill;
}
public Company getCompany() {
return company;
}
public void setCompany(Company company) {
this.company = company;
}
public String getPolicyNumber() {
return policyNumber;
}
public void setPolicyNumber(String policyNumber) {
this.policyNumber = policyNumber;
}
public BigDecimal getRate() {
return rate;
}
public void setRate(BigDecimal rate) {
this.rate = rate;
}
public Float getDiscountPercent() {
return discountPercent;
}
public void setDiscountPercent(Float discountPercent) {
this.discountPercent = discountPercent;
}
public String getDescription() {
return description;
}
public void setDescription(String description) {
this.description = description;
}
@Override
public int hashCode() {
final int prime = 31;
int result = 1;
result = prime * result + ((id == null) ? 0 : id.hashCode());
result = prime * result
+ ((validFrom == null) ? 0 : validFrom.hashCode());
result = prime * result + ((vehicle == null) ? 0 : vehicle.hashCode());
return result;
}
@Override
public boolean equals(Object obj) {
if (this == obj)
return true;
if (obj == null)
return false;
if (!(obj instanceof TraInsurance))
return false;
TraInsurance other = (TraInsurance) obj;
if (id == null) {
if (other.id != null)
return false;
} else if (!id.equals(other.id))
return false;
if (validFrom == null) {
if (other.validFrom != null)
return false;
} else if (!validFrom.equals(other.validFrom))
return false;
if (vehicle == null) {
if (other.vehicle != null)
return false;
} else if (!vehicle.equals(other.vehicle))
return false;
return true;
}
}
答案 0 :(得分:12)
请在此用例中明确使用 JOIN :
SELECT ve, MAX(v.validTill)
FROM TraInsurance v JOIN v.vehicle ve
GROUP BY ve
ORDER BY MAX(v.validTill)
答案 1 :(得分:6)
答案 2 :(得分:2)
如果您在GROUP BY中传递实体,Hibernate会自动将其 id 添加到基础数据库的转换后的SQL中。此外,GROUP BY中的值必须存在于SELECT子句中。因此,您可以选择其ID,而不是选择整个对象,然后从那些 ids 中,您可以再次检索该对象。
SELECT DISTINCT v.vehicle.id, max(v.validTill)
FROM TraInsurance v
GROUP BY v.vehicle.id
ORDER BY max(v.validTill)
如果需要时间并且需要DB命中从其ID中检索 Vehicle 对象,则可以在SELECT中选择所有 Vehicle 的属性并将其放入通过...分组。然后,您可以从这些属性构造 Vehicle 对象,而无需访问DB。