Question

我正在尝试更新我能够查看的值。它似乎没有错误，但似乎没有任何更新。任何人都可以帮我确定它没有更新的地方吗？请

<?php

 // check for errors
 ini_set('display_errors', 1);

 //calls connection
require_once('connection.php');

 //view first table
 $ResultSets = getResults("members");

 echo "<table border='1' cellpadding='6'>";
echo "<tr> <th>member_id</th> <th>first_name</th> <th>second_name</th> <th>Email</th> ";

foreach ($ResultSets as $record) {
echo "<form action=index.php method=post>";
echo "<tr>";
echo "<td>" . "<input type=text name=topic value =" . $record ['member_id'] . " </td>";
echo "<td>" . "<input type=text name=topic value =" . $record ['first_name'] . " </td>";
echo "<td>" . "<input type=text name=topic value =" . $record ['second_name'] . " </td>";
echo "<td>" . "<input type=text name=topic value =" . $record ['email'] . " </td>";
echo "<td>" . "<input type=hidden name=hidden value =" . $record ['member_id'] . " </td>";
//echo "</tr>";
echo "<input type=submit name=update value=Update>" . " </td>";
 }

echo "<table>";
echo "</form>";

 if (isset($_POST['update'])) {

$updateQuery = "UPDATE members SET first_name='$_POST[first_name]', second_name='$_POST[second_name]', email='$_POST[email]' WHERE  member_id='$_POST[hidden]'";

mysql_query($updateQuery);
}
 ?>

Answer 1

您的所有输入都有主题名称。

echo "<td>" . "<input type=text name=topic value =" . $record ['member_id'] . " </td>";
echo "<td>" . "<input type=text name=topic value =" . $record ['first_name'] . " </td>";
echo "<td>" . "<input type=text name=topic value =" . $record ['second_name'] . " </td>";
echo "<td>" . "<input type=text name=topic value =" . $record ['email'] . " </td>";

需要更改为

echo "<td>" . "<input type=text name=member_id value =" . $record ['member_id'] . " </td>";
echo "<td>" . "<input type=text name=first_name value =" . $record ['first_name'] . " </td>";
echo "<td>" . "<input type=text name=second_name value =" . $record ['second_name'] . " </td>";
echo "<td>" . "<input type=text name=email value =" . $record ['email'] . " </td>";

Answer 2

此外，您还将member_id作为字符串传递，而我确定它是数据库中的整数。尝试：

$updateQuery = "UPDATE members SET first_name='$_POST[first_name]', second_name='$_POST[second_name]', email='$_POST[email]' WHERE member_id=$_POST[hidden]";

更新到我的数据库不能在PHP中工作

2 个答案: