如何在单引号PHP中显示双引号

Question

我有一个PHP echo语句：

echo "stores[".$row['BarID']."] = [". $row['BarName'] . ", " . $row['Address']. ",". $row['City']. "," . $row['State']. " 0". $row['ZipCode']. "," . $row['PhoneNumber']. ",". $row['Lattitude']. ",".$row['Longitude']. "]". ";<br>";  

输出：

stores[0] = [The Ale 'N 'Wich Pub , 246 Hamilton St ,New Brunswick,NJ 08901,732-745-9496 ,40.4964198,-74.4561079];

但我会像双语这样输出：

stores[0]=["The Ale 'N 'Wich Pub", "246 Hamilton St, New Brunswick, NJ 08901", "732-745-9496 Specialty: Sport", "40.4964198", "-74.4561079"];

我已经查看了PHP网站上的PHP字符串函数手册，但仍然不明白我如何实现它。非常感谢您的帮助。

Answer 1

您错过的关键字是“转义”（请参阅​​Wiki）。最简单的例子：

echo "\"";

会输出：

"

修改

基本解释是 - 如果你想在双引号终止字符串中放入双引号你必须转义它，否则你会得到语法错误。

示例：

echo "foo"bar";
         ^
         +- this terminates your string at that position so remaining bar"
            causes syntax error. 

为了避免，你需要逃避双重报价：

echo "foo\"bar";
         ^
         +- this means the NEXT character should be processed AS IS, w/o applying
            any special meaning to it, even if it normally has such. But now, it is
            stripped out of its power and it is just bare double quote.

所以你的（它是字符串的一部分，但是你应该明白这一点并自己做其余的事情）：

 echo "stores[".$row['BarID']."] = [". $row['BarName'] . ", " . $row['Address'] .

应该是：

 echo "stores[".$row['BarID']."] = [\"". $row['BarName'] . "\", \"" . $row['Address']. "\"

等等。