Question

我想将movies_iit结构的6部电影的内容写入我的文件fout（＆＃34; data.dat＆＃34;）。

// array of structures
#include <iostream>
#include <string>
#include <sstream>
#include <istream>
#include <stdio.h>
#include <cctype>
#include <fstream>
using namespace std;

#define NUM_MOVIES 6
//###################################################################################################    ################
//structure
//###################################################################################################    ################
struct movies_iit{
    string title;
    int year;
} films [NUM_MOVIES];
//global variables
char title [20], y, n;
int year;
string search;
//function 1
void sort_on_title(movies_iit films[], int n)
{
//Local struct variable used to swap records
movies_iit temp;    

for(int i=0; i<n-1; i++)
    {
for(int i=0; i<n-1; i++)
        {
/*If s[i].title is later in alphabet than
s[i+1].title, swap the two records*/
        if(films[i].title>films[i+1].title)
            {
                temp = films[i];
                films[i] = films[i+1];
                films[i+1] = temp;
            }  
        }
    }
}
//end function 1
//function query1 prototype
void query1 (movies_iit movie);
//function query2 prototype
void query2 (movies_iit movie);
//function 2 prototype
void printmovie (movies_iit movie);
//###################################################################################################    ################
//beginning of main
//###################################################################################################    ################
int main ()
{
//login
//username: user
//password: word
string mystr;
int n;
char response;
string pass;
string name;
//output object
ofstream fout ("data.dat");
cout << "enter your username "<<endl;
cin >> name;
cout << "enter your password "<<endl;
cin >> pass;

cout << "\n" << endl;

if (name == "user" && pass == "word")
    cout << "Welcome, user." << endl;
else
{cout << "###" <<  "unrecognized username/password combination" << "\t" << "please try again"     << "###" << endl;
    system("PAUSE");
    return 0;
}

cin.ignore(std::numeric_limits<std::streamsize>::max(), '\n');

cout << "\n" << endl;

for (n=0; n<NUM_MOVIES; n++)
{
    cout << "Enter title: ";
    getline (cin,films[n].title);
    cout << "Enter year: ";
    getline (cin,mystr);
    stringstream(mystr) >> films[n].year;
}
//sort records, function 1 call
sort_on_title(films, NUM_MOVIES);
cout << "\nYou have entered these movies:\n";
for (n=0; n<NUM_MOVIES; n++) 
    printmovie (films[n]);  //function 2 call
//Query 1
cout << "Perform an alphabetical search? (y/n)" << endl;
cin >> response;

if (response == 'y')
    {cout << "Please enter title" << endl;
    cin >> title;
    for (n=0; n<NUM_MOVIES; n++)
        {query1 (films[n]);
            response == n;
        }
    }
else if (response == 'n')
    cout << "\n" << endl;
else
    cout << "invalid entry" << endl;
//Query 2
cout << "Perform a chronological search? (y/n)" << endl;
cin >> response;
//greater than
if (response == 'y')
{   cout << "greater than what year?" << endl;
    cin >> year;
    for (n=0; n<NUM_MOVIES; n++)
        {   query2 (films[n]);
        }
}
else if (response == 'n')
    cout << "Thank you, goodbye." << endl;
else
    cout << "invalid entry" << endl;
system("pause");
return 0;
}
//###################################################################################################    ################
//end of main
//###################################################################################################    ################
//function 2 definition
void printmovie (movies_iit movie)
{
  cout << movie.title;
  cout << " (" << movie.year << ")\n";
}
//function query1 defintion
void query1 (movies_iit movie)
{
  if (movie.title == title)
      {cout << " >> " << movie.title;
  cout << " (" << movie.year << ")\n";}
  else
      {cout << movie.title;
  cout << " (" << movie.year << ")\n";}
}
//function query2 definition
void query2 (movies_iit movie)
{
  if (movie.year >= year)
      {cout << movie.title;
        cout << " (" << movie.year << ")\n";
      }
}

此代码目前设计为分别接收6个电影名称和发布日期，并允许用户通过它们进行查询。我现在想把6个元素中的每个元素的内容写成我文件中的单独行。我该怎么做呢？

Answer 1

嗯，你已经编写了所需的所有代码，你只需要稍微重新安排一下。

for (int i = 0; i < NUM_MOVIES; ++i)
{
    fout << films[i].title;
    fout << " (" << films[i].year << ")\n";
}

BTW你的排序代码不起作用。

通过fstream将结构中的文本写入文件

1 个答案: