Question

我目前正在尝试搜索数组列表并显示与用户查询匹配的结果。我继续得到一个ConcurrentModificationException，不知道如何解决它。我可搜索的活动中的代码如下：

public class SearchActivity extends Activity {

ListView l;

String[] testArray;
List<String> testArrayList;
ArrayAdapter<String> adapter;

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_search);

    testArray = getResources().getStringArray(R.array.list);
    testArrayList = new ArrayList<String>(Arrays.asList(testArray));

    l = (ListView) findViewById(R.id.list);
    adapter = new ArrayAdapter<String>(this, android.R.layout.simple_list_item_1, testArrayList);
    l.setAdapter(adapter);

    handleIntent(getIntent());
}

protected void onNewIntent(Intent intent) {
    handleIntent(intent);
}

private void handleIntent(Intent intent) {
    if (Intent.ACTION_SEARCH.equals(intent.getAction())) {
        String query = intent.getStringExtra(SearchManager.QUERY);
        //Log.d("Event", query);

        search(query);
    }
}

private void search(String query){

    for (String element : testArrayList) {
        if (!element.contains(query)) {
            testArrayList.remove(element);
        }
    }
}

@Override
public boolean onCreateOptionsMenu(Menu menu) {
    // Inflate the menu; this adds items to the action bar if it is present.
    getMenuInflater().inflate(R.menu.search, menu);

    return true;
}

}

Answer 1

问题在于：

for (String element : testArrayList) {
    if (!element.contains(query)) {
        testArrayList.remove(element);
    }
}

在迭代集合时不应删除元素，将其更改为此类（未测试）：

Iterator<String> iter = testArrayList.iterator();
while(iter.hasNext()){
   if (!iter.next().contains(query)) {
        iter.remove();
}

Android搜索字符串数组

1 个答案: