Question

我正在使用silverlight编程（c＃.net）

假设我有一个“数据”类型列表

    public class data    
{
    public string QUOTE_ID { get; set; }
    public string EVENT_ACTION_CD { get; set; }
    public string CUSTOMER_NAME { get; set; }
    public string ADAPTIV_CODE { get; set; }
}

问题是一些数据来自1个数据库而其他数据来自另一个数据库，所以现在我分两步得到数据 - 所以我有这样的东西（使用随机数）：

input1 = new List<data> //data return from database 1 
//(the data is actually returned as a datable which i convert to a list      
//to put to a datagrid, but the end result is shown below)
{
    new data { QUOTE_ID = "1", EVENT_ACTION_CD = "2"},
    new Project { QUOTE_ID = "2", EVENT_ACTION_CD = "4"},
    new Project { QUOTE_ID = "3", EVENT_ACTION_CD = "5"}
};

input2 = new List<data> //data return from database 2    
{
    new data { QUOTE_ID = "1", CUSTOMER_NAME = "2", ADAPTIV_CODE ="5"},
    new Project { QUOTE_ID = "2", CUSTOMER_NAME = "4", ADAPTIV_CODE = "5"},
    new Project { QUOTE_ID = "3", CUSTOMER_NAME = "5", ADAPTIV_CODE = "7"}
};

所以我应该有2个列表输入1：

(1, 2, null, null
2, 4, null, null
3, 5, null, null)

和输入2：

(1, null, 2, 5
2, null, 4, 5
3. null, 5, 7)

如何将它们连接在一起形成一个输入列表成为

(1, 2, 2, 5
2, 4, 4, 5
3, 5, 5, 7)

Answer 1

正常的for循环对你有用：

for(int i = 0; i < input1.Count; i++){
 if(input1[i].QUOTE_ID == null) input1[i].QUOTE_ID = input2[i].QUOTE_ID;
 if(input1[i].EVENT_ACTION_CD == null) input1[i].EVENT_ACTION_CD = input2[i].EVENT_ACTION_CD;
 if(input1[i].CUSTOMER_NAME == null) input1[i].CUSTOMER_NAME = input2[i].CUSTOMER_NAME;
 if(input1[i].ADAPTIV_CODE == null) input1[i].ADAPTIV_CODE = input2[i].ADAPTIV_CODE;
}

结果将保存到input1。该代码还假设input1和input2具有相同的Count。

Answer 2

var input3 = input1.Join（输入2 d1 =＆gt; d1.QUOTE_ID， d2 =＆gt; d2.QUOTE_ID，（d1，d2）=＆gt;新数据（） { QUOTE_ID = d1.QUOTE_ID， EVENT_ACTION_CD = d1.EVENT_ACTION_CD， CUSTOMER_NAME = d2.CUSTOMER_NAME， ADAPTIV_CODE = d2.ADAPTIV_CODE } ）;

Answer 3

将linq与join运算符一起使用。

请参阅http://code.msdn.microsoft.com/101-LINQ-Samples-3fb9811b

var resultList = (from item in input1 
                 join item2 in input2 on item2.QUOTE_ID equals input2.QUOTE_ID
                 let item.CUSTOMER_NAME = item2.CUSTOMER_NAME
                 let item.ADAPTIV_CODE = item2.ADAPTIV_CODE 
                 select item).ToList();

在c＃中合并2个复杂列表

3 个答案: