Question

我正在编写一个与第三方软件接口的脚本。

他们以以下格式发送字符串：

sender-ip=10.10.10.10, primary site location=peachtree street, created by=jsmith

但是，当脚本执行时

Write-host $args

这是输出

sender-ip=10.10.10.10 primary site location=peachtree street created by=jsmith

如何使用逗号保留原始输入字符串？

编辑：

下面是代码snippit

$args = $args.ToString()
write-host '$args is' $args

foreach ($i in $args){
   $line_array+= $i.split(",")
   write-host '$line_array is' $line_array

}

foreach ($j in $line_array){
    $multi_array += ,@($j.split("="))
}

foreach ($k in $multi_array){
    $my_hash.add($k[0],$k[1])

}


$Sender_IP = $my_hash.Get_Item("sender-ip")

当我用

执行代码时

script.ps1 sender-ip=10.10.10.10, primary site location=peachtree street, created by=jsmith

我得到了

$args is System.Object[]
$line_array is System.Object[]
$Sender_IP is

Answer 1

它将其解释为多个参数。你需要引用整个事情，所以它只知道一个论点：

&{Write-Host $args} sender-ip=10.10.10.10, primary site location=peachtree street, created by=jsmith
&{Write-Host $args} 'sender 10.10.10.10, primary site location=peachtree street, created by=jsmith'

sender-ip=10.10.10.10 primary site location=peachtree street created by=jsmith
sender 10.10.10.10, primary site location=peachtree street, created by=jsmith

Powershell - $ args删除了逗号

1 个答案: