用Python划分

Question

我是新的Python，我正在练习一些东西，但我似乎无法解决为什么我的代码中显示的下面4个等级不能正确地除以4.例如，我将所有等级输入为2并显示为6.5作为总成绩平均值。

下面是代码：

#FinalGrade
Student = str(input("Student Name: "))
Grade1 = int(input("Enter Student's First Grade: "))
Grade2 = int(input("Enter Student's Second Grade: "))
Grade3 = int(input("Enter Student's Third Grade: "))
Grade4 = int(input("Enter Student's Fourth Grade: "))

print ("Total Grade Average: %G" % (Grade1+Grade2+Grade3+Grade4/4))

print ("%s has:" % (Student))

if Grade1+Grade2+Grade3+Grade4/4 < 40:
print ("Failed!")
if Grade1+Grade2+Grade3+Grade4/4 > 40:
print ("Passed!")

Answer 1

更改

Grade1+Grade2+Grade3+Grade4/4

到

(Grade1+Grade2+Grade3+Grade4)/4

在此处查看不同之处：

>>> 1 + 2 +3 +4/4
7
>>> (1+2+3+4)/4
2
>>> 

在第一种情况下，该值被评估为

Grade1+Grade2+Grade3+(Grade4/4)

你想要的是

(Grade1+Grade2+Grade3+Grade4)/4

考虑将其提取为局部变量。

#FinalGrade
Student = str(input("Student Name: "))
Grade1 = int(input("Enter Student's First Grade: "))
Grade2 = int(input("Enter Student's Second Grade: "))
Grade3 = int(input("Enter Student's Third Grade: "))
Grade4 = int(input("Enter Student's Fourth Grade: "))

average =  (Grade1+Grade2+Grade3+Grade4 )/4
print ("Total Grade Average: %G" % (average))

print ("%s has:" % (Student))

if average < 40:
    print ("Failed!")
if average > 40:
    print ("Passed!")

#what if average == 40 ?

要在同一行输入所有内容，

passed_or_failed = "Passed"
if average < 40:
    passed_or_failed = 'Failed'

print ("%s has: %s" % (Student, passed_or_failed))

Answer 2

这不是python。您需要了解数学运算符的优先级规则。

你只将Grade4除以4，而不是等级的总和。

Answer 3

由于order of operations，实际评估的是

Grade1 + Grade2 + Grade3 + (Grade4 / 4)

要解决此问题，请在成绩周围使用括号或单独求和：

gradeAvg = (Grade1 + Grade2 + Grade3 + Grade4) / 4

gradeSum = Grade1 + Grade2 + Grade3 + Grade4
gradeAvg = gradeSum / 4

Answer 4

if (Grade1+Grade2+Grade3+Grade4)/4 < 40: