Question

我有一些HTML：）

<div class="categories">
    <div class="list-group">
        <a class="root list-group-item" id="427" style="display: block;"><span class="glyphicon indent0 glyphicon-chevron-down"></span><span>Home</span></a>
        <a class="list-group-item first active" id="428" style="display: block;"><span class="glyphicon indent1 glyphicon-chevron-right"></span><span>Images</span></a>
        <a class="list-group-item child" id="431" style="display: none;"><span class="glyphicon glyphicon-chevron-right indent2"></span><span>Sub category</span></a>
        <a class="list-group-item child" id="433" style="display: none;"><span class="glyphicon indent3"></span><span>Super sub</span></a>
        <a class="list-group-item first" id="429" style="display: block;"><span class="glyphicon glyphicon-chevron-right indent1"></span><span>Videos</span></a>
        <a class="list-group-item child" id="432" style="display: none;"><span class="glyphicon indent2"></span><span>Another sub</span></a>
        <a class="list-group-item first" id="430" style="display: block;"><span class="glyphicon indent1"></span><span>Documents</span></a>
    </div>
</div>

我有这个功能：

$(".glyphicon", treeRoot).on('click', function (e) {
    e.stopPropagation();

    var $glyph = $(this);
    var $item = $glyph.parent();
    var indent = $item.find(".glyphicon").prop('className').match(/\b(indent\d+)\b/)[1];

    if (indent != undefined) {
        var $children = $item.nextUntil("a:has(." + indent + ")");

        if ($glyph.hasClass("glyphicon-chevron-right")) {
            $glyph
                .addClass('glyphicon-chevron-down')
                .removeClass("glyphicon-chevron-right");

            if ($children != null) $children.show();
        } else {
            $glyph
                .addClass('glyphicon-chevron-right')
                .removeClass("glyphicon-chevron-down");

            if ($children != null) $children.hide();
        }
    }
});

所以基本上，当点击图标时，它会显示或隐藏孩子。问题是，它显示了所有孩子（indent2和indent3），但我只是想让它显示直接的孩子（在这个例子中为indent2）。

有人能给我一些关于如何做到这一点的见解吗？

干杯，

/ r3plica

Answer 1

尝试

var num = parseInt(indent.match(/(\d+)$/)[1], 10);
var $children = $item.nextUntil("a:not(:has(.indent" + (num + 1) + "))");

演示：Fiddle

使用nextUntil立即获取孩子

1 个答案: