Question

如果我有这样的字符串：

 String JSLines =  "DefineEvent(20140208,'Starting of Study for (old and new) student's ','','',17,5)";

如何得到以下结果：

20140208|Starting of Study for (old and new) student's

我尝试这样做：

 strDate = JSLines.Substring(JSLines.LastIndexOf("(") + 1, 8);
 toolTip = JSLines.Substring(JSLines.IndexOf(',') + 2, (JSLines.IndexOf(',', JSLines.IndexOf(',') + 1)) - (JSLines.IndexOf(',') + 3));

但在我的第二个参数

中遇到'或(时失败了

Answer 1

你可以试试这个

var substring = string.Join("|", "".Split(',').Take(2).Select(x => x.Trim('\'')));

当然，只有当字符串不包含,时，这才有效，但在这种情况下，它们不是

Answer 2

您只能使用字符串方法：

String JSLines = "DefineEvent(20140208,'Starting of Study for (old and new) student's ','','',17,5)";

string result = JSLines;
int methodBodyStart = JSLines.IndexOf("DefineEvent(");
if (methodBodyStart >= 0)
{
    methodBodyStart += "DefineEvent(".Length;
    int methodBodyEnd = JSLines.LastIndexOf(')');
    if (methodBodyEnd >= 0)
    {
        string methodBody = JSLines.Substring(methodBodyStart, methodBodyEnd - methodBodyStart);
        var twoParams = methodBody.Split(',')
           .Select(str => str.Trim(' ', '\'')).Take(2);
        result = string.Join("|", twoParams);
    }
}

Demonstration

Answer 3

你可以试试这个

var str = "DefineEvent(20140208,'Starting of Study for (old and new) student's ','','',17,5)";
        var arr = str.Split(new[] {",'","',", "DefineEvent(" }, StringSplitOptions.None);
        var result = String.Join("|", new[] {arr[1], arr[2]});

如何对中间的许多分隔符进行子串

3 个答案: