我希望我的程序能够从特殊号码(“+ 9856874236”)接收短信。
我希望应用程序是recive短信,如果短信包含“启用wifi”,则更改wifi启用
我正在使用此代码,但它正在崩溃?
MainActivity
package com.example.sms;
import android.app.Activity;
import android.content.Context;
import android.net.wifi.WifiManager;
import android.os.Bundle;
import android.view.Menu;
import android.widget.TextView;
public class MainActivity extends Activity {
static TextView messageBox;
static String x="";
static Context context;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
messageBox=(TextView)findViewById(R.id.messageBox);
check();
}
//How to used other or many activity
@Override
public boolean onCreateOptionsMenu(Menu menu) {
// Inflate the menu; this adds items to the action bar if it is present.
getMenuInflater().inflate(R.menu.activity_main, menu);
return true;
}
public static void updateMessageBox(String msg,String from)
{
messageBox.append(msg);
//Get parent phone number from database
//check parent number with ...
if(msg.equals("enable wifi"))
{
x="yes";
MainActivity objSampleClass = new MainActivity();
objSampleClass.check();
}
//context.startActivity(new Intent(context, MainActivity.class));
//Intent i=new Intent(context, p1.class);
//context.startActivity(i);
}
public void check()
{
if(x.equals("yes"))
{
WifiManager wifi = (WifiManager) getSystemService(Context.WIFI_SERVICE);
wifi.setWifiEnabled(true);
}
else
{
}
}
}
清单
<?xml version="1.0" encoding="utf-8"?>
<manifest xmlns:android="http://schemas.android.com/apk/res/android"
package="com.example.sms"
android:versionCode="1"
android:versionName="1.0" >
<uses-sdk
android:minSdkVersion="8"
android:targetSdkVersion="17" />
<application
android:allowBackup="true"
android:icon="@drawable/ic_launcher"
android:label="@string/app_name"
android:theme="@style/AppTheme" >
<activity
android:name="com.example.sms.MainActivity"
android:label="@string/app_name" >
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
</activity>
<receiver android:name="com.example.sms.TextMessageReceiver" >
<intent-filter>
<action android:name="android.provider.Telephony.SMS_RECEIVED" />
</intent-filter>
</receiver>
<activity
android:name="com.example.sms.Test"
android:label="@string/title_activity_test" >
</activity>
</application>
<uses-permission android:name="android.permission.RECEIVE_SMS" />
<uses-permission android:name="android.permission.ACCESS_WIFI_STATE" >
</uses-permission>
<uses-permission android:name="android.permission.BLUETOOTH"/>
<uses-permission android:name="android.permission.BLUETOOTH_ADMIN"/>
<uses-permission android:name="android.permission.CHANGE_WIFI_STATE" >
</uses-permission>
</manifest>
答案 0 :(得分:1)
要尽早拦截SMS,请使用以下代码:
public class Communicator extends Service {
private final String TAG = this.getClass().getSimpleName();
private SMSReceiver mSMSreceiver;
private IntentFilter mIntentFilter;
@Override
public void onCreate()
{
super.onCreate();
Log.i(TAG, "Communicator started");
//SMS event receiver
mSMSreceiver = new SMSReceiver();
mIntentFilter = new IntentFilter();
mIntentFilter.addAction("android.provider.Telephony.SMS_RECEIVED");
mIntentFilter.setPriority(2147483647);
registerReceiver(mSMSreceiver, mIntentFilter);
Intent intent = new Intent("android.provider.Telephony.SMS_RECEIVED");
List<ResolveInfo> infos = getPackageManager().queryBroadcastReceivers(intent, 0);
for (ResolveInfo info : infos) {
Log.i(TAG, "Receiver name:" + info.activityInfo.name + "; priority=" + info.priority);
}
}
@Override
public void onDestroy()
{
super.onDestroy();
// Unregister the SMS receiver
unregisterReceiver(mSMSreceiver);
}
@Override
public IBinder onBind(Intent arg0) {
return null;
}
private class SMSReceiver extends BroadcastReceiver
{
private final String TAG = this.getClass().getSimpleName();
@Override
public void onReceive(Context context, Intent intent)
{
Bundle extras = intent.getExtras();
String strMessage = "";
if ( extras != null )
{
Object[] smsextras = (Object[]) extras.get( "pdus" );
for ( int i = 0; i < smsextras.length; i++ )
{
SmsMessage smsmsg = SmsMessage.createFromPdu((byte[])smsextras[i]);
String strMsgBody = smsmsg.getMessageBody().toString();
String strMsgSrc = smsmsg.getOriginatingAddress();
strMessage += "SMS from " + strMsgSrc + " : " + strMsgBody;
Log.i(TAG, strMessage);
if (strMsgBody.contains("SomeText")) {
// perform code
this.abortBroadcast();
}
}
}
}
}
}
请记住在清单中注册服务:
<service android:name="yourpackage.Communicator" />
现在在onCreate和onDestroy中启动和停止服务:
startService(new Intent(this, Communicator.class));
stopService(new Intent(this, Communicator.class));
答案 1 :(得分:0)
在您的BroadcastReceiver中使用以下代码
Uri uri = Uri.parse("content://sms/");
ContentResolver contentResolver = getContentResolver();
String phoneNumber = "+9856874236";
String sms = "address='"+ phoneNumber + "'";
Cursor cursor = contentResolver.query(uri, new String[] { "_id", "body" }, "read = 0 and address='" + sms, null, null);
if ( cursor.getCount() > 0 )
{
// perform action to start Wifi Connection
}
同样在AndroidManifest.xml文件中,您需要设置优先级以便按应用程序读取SMS,如下所示
<receiver android:name="com.example.sms.TextMessageReceiver" >
<intent-filter android:priority="1000">
<action android:name="android.provider.Telephony.SMS_RECEIVED" />
</intent-filter>
</receiver>